1. Joined
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    29 Jul '04 18:21
    Using only two 2's and any combination of mathematical signs, symbols and functions can you make 5?

    -Ray.
  2. Standard memberroyalchicken
    CHAOS GHOST!!!
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    30 Jul '04 04:32
    Originally posted by rgoudie
    Using only two 2's and any combination of mathematical signs, symbols and functions can you make 5?

    -Ray.
    2 + 2 + 1.

  3. in complete
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    30 Jul '04 07:53
    Originally posted by rgoudie
    Using only two 2's and any combination of mathematical signs, symbols and functions can you make 5?

    -Ray.
    a = 2/2
    5 = a+a+a+a+a
  4. Joined
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    30 Jul '04 13:32
    Originally posted by kody magic
    a = 2/2
    5 = a+a+a+a+a
    The correct solution will use no other digits other than two 2s. You may use any mathematical symbols, which do not include any algebraic variables. This is not a trick question.

    -Ray.
  5. Standard memberCribs
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    30 Jul '04 14:12
    2 + 2 + e/e
  6. Joined
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    30 Jul '04 14:22
    Originally posted by Cribs
    2 + 2 + e/e
    I must be more precise. 🙂

    Use only two 2s as well as mathematical symbols and modifiers. No lettered-quantites are required.

    -Ray.
  7. Standard memberCribs
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    30 Jul '04 14:421 edit
    2 + 2 + |{ {} }|

    That is, 4 plus the size of the set whose single member is the empty set.
  8. Joined
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    30 Jul '04 15:01
    Originally posted by Cribs
    2 + 2 + |{ {} }|

    That is, 4 plus the size of the set whose single member is the empty set.
    Looks valid. There is at least one more solution.

    -Ray.
  9. Standard memberpsychopath42
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    30 Jul '04 17:27
    Originally posted by rgoudie
    Using only two 2's and any combination of mathematical signs, symbols and functions can you make 5?

    -Ray.
    ceil( sqrt( 22 ) )
  10. Standard memberroyalchicken
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    30 Jul '04 17:37
    Do the axiomatic set theory thing:

    5 = (2^2)'
  11. Joined
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    30 Jul '04 18:21
    Originally posted by psychopath42
    ceil( sqrt( 22 ) )
    Not the particular solution that I had in mind, but I'll accept your solution! 🙂

    -Ray.
  12. Donation!~TONY~!
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    30 Jul '04 18:211 edit
    Wow.....I was about to post something but I was using more than 2 2's....I was wondering why noone had said what I was posting already!
  13. Joined
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    30 Jul '04 18:21
    Originally posted by !~TONY~!
    what about 2 + 2 + (2/2) ?
    The problem wit this solution is that the digit 2 appears four times.

    -Ray.
  14. Donation!~TONY~!
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    30 Jul '04 18:22
    yessir....hence the edit above.....I thought that was way too easy! I am sitting here wondering why all these people are going deep into math......I SUCK!
  15. Joined
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    30 Jul '04 18:23
    Originally posted by !~TONY~!
    yessir....hence the edit above.....I thought that was way too easy! I am sitting here wondering why all these people are going deep into math......I SUCK!
    Come on, now. Don't be so hard on yourself. 🙂

    -Ray.
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