@joe-shmo
10 ways to draw the first card
5 evens
9 ways to draw the 2nd card
5 odds
4 evens
5 odds
9 ways to draw the 2nd card
5 evens
4 odds
cases tally, resultant sum parity
25 e-o, o
20 e-e, e
25 o-e, o
20 o-o, e
5/9 chance of being odd
4/9 chance of being even
P.S. I feel like an RHP god, getting my text to indent like that.
@bigdoggproblem saidCorrect!
@joe-shmo
10 ways to draw the first card
5 evens
9 ways to draw the 2nd card
5 odds
4 evens
5 odds
9 ways to draw the 2nd card
5 evens
4 odds
cases tally, resultant sum parity
25 e-o, o
20 e-e, e
25 o-e, o
20 o-o, e
5/9 chance of being odd
4/9 chance of being even
P.S. I feel like an RHP god, getting my text to indent like that.
There are C(10,2) = 45 ways to draw two cards
The sum is even if they have the same parity:
Both even:
C( 5,2) = 10 ways
Both odd:
C( 5,2) = 10 ways
20 ways
The sum is odd if thy have opposite parity
5*5 = 25 Ways
P( even sum ) = 20/45 = 4/9
and
P( odd sum ) = 25/45 = 5/9
P.S. The reply/quote reveals none of your magic for indenting the text! Are you willing to share this valuable information, or are we "lesser's" left to marvel at your greatness?