04 Nov '10 15:55

So I put my above ground pool, 7 meters across, to sleep for the winter, it freezes here, get maybe 100 mm of ice. But not now. It is raining like the dickens here for a few days. The cover is slanting down at 45 degrees, meeting the waterline 500 mm below where the top of the cover is.

It meets the water and flattens out 500 mm in so the flat part of the cover is 6 meters across. Assuming everything atomically smooth, a truncated cone starting at 7 meters across meets a flat which is 6 meters across.

The rain has caused an accumulation of 40 mm exactly. If it was a true cylindrical section you can say there was 40 mm of rain. But the cone shaped section raises the level of the water a bit. What is the true amount of rain?

Also, how deep does the cone peak go down? the water is 1 meter deep and the wall holding the pool together is 1.50 meters high, so does the peak of the cone extend underground if it was a full cone or does it come to focus above the bottom of the pool if it were real?

It meets the water and flattens out 500 mm in so the flat part of the cover is 6 meters across. Assuming everything atomically smooth, a truncated cone starting at 7 meters across meets a flat which is 6 meters across.

The rain has caused an accumulation of 40 mm exactly. If it was a true cylindrical section you can say there was 40 mm of rain. But the cone shaped section raises the level of the water a bit. What is the true amount of rain?

Also, how deep does the cone peak go down? the water is 1 meter deep and the wall holding the pool together is 1.50 meters high, so does the peak of the cone extend underground if it was a full cone or does it come to focus above the bottom of the pool if it were real?