1. Donationbelgianfreak
    stitching you up
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    26 Aug '03 10:33
    Originally posted by Fiathahel
    But then AD/DB * BE/EC * CF/FA =/= 1 .
    (I notice now I mistyped CF/FA the first time)

    aaargh, more maths!!!!
  2. Standard memberFiathahel
    Artist in Drawing
    in your fridge
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    26 Aug '03 10:461 edit
    Originally posted by belgianfreak
    aaargh, more maths!!!!
    Sorry, I forgot this was a "no math" Thread. It won't happen again 🙂
  3. Donationbelgianfreak
    stitching you up
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    26 Aug '03 11:07
    Originally posted by Fiathahel
    Sorry, I forgot this was a "no math" Thread. It won't happen again 🙂
    he he he 🙂 no problem here - except that the maths puzzles make my brain liquify and attempt to escape out of my left ear 😉
  4. Joined
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    27 Aug '03 08:52
    Originally posted by richjohnson
    I don't think that's true in the general case. If D's near B, E's near C and F's near A, then AE and CD intersect near C, and AE and BF intersect near A.
    If D's near B, E's near C and F's Near A: Then BF, AE and CD don't intersect at one point. The general proof is still possible 😉
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