Posers and Puzzles
22 Aug 03
23 Aug 03
Originally posted by belgianfreak- they are all on the same line
find the connection between these words:
mug elf kid low wag age hop eat tag
- they are all writen by belgianfreak
- they all consist out of three letters (I personaly want to thank TheMaster37 for discovering that)
and last but not least
- they are all annoying me cause I can't see which connection is ment
😕
24 Aug 03
Originally posted by belgianfreakThere are at least two people here who study math...
bump
come on people - are you only capable of hiding behind math that none of have studued and therefore have no hope of understaning. It's not that hard (honest), it just involves a touch of lateral thinking.
25 Aug 03
Originally posted by royalchickenThe Master and I both study math. (at least that's what we should do here instead of posting in the forums 🙂 )
And who might they be? If you're one, get a star and get in the Cult of Maths!
Perhaps now is a good time to become a member. Who doesn't want to be in the Cult of Maths. I haven't got a creditcard nor a us bank account though, so it might take some while.
25 Aug 03
Originally posted by royalchickenI'm interested in tha areas of financial mathematics, which is for the most part about stochastics. But also geometry interests me.
What areas of math interest you in particular?
Perhaps you know this. I've got a triangle ABC. On the line AB I take a point D, on BC I take E and on CA F. Show that if AE, BF, CD intersect in one point, AD/DB * BE/EC * CF/CA = 1.
It is easy to prove for some special cases, but I can't do it in general.
25 Aug 03
Originally posted by FiathahelI don't think that's true in the general case. If D's near B, E's near C and F's near A, then AE and CD intersect near C, and AE and BF intersect near A.
I'm interested in tha areas of financial mathematics, which is for the most part about stochastics. But also geometry interests me.
Perhaps you know this. I've got a triangle ABC. On the line AB I take a point D, on BC I take E and on CA F. Show that if AE, BF, CD intersect in one point, AD/DB * BE/EC * CF/CA = 1.
It is easy to prove for some special cases, but I can't do it in general.