Posers and Puzzles

Posers and Puzzles

  1. Donationbelgianfreak
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    22 Aug '03 12:52
    find the connection between these words:

    mug elf kid low wag age hop eat tag
  2. Standard memberTheMaster37
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    22 Aug '03 14:21
    Originally posted by belgianfreak
    find the connection between these words:

    mug elf kid low wag age hop eat tag
    All words have three letters...

    Tag an elf to wag and hop is to mug a kid of low age to eat
  3. Donationbelgianfreak
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    23 Aug '03 17:001 edit
    bump

    come on people - are you only capable of hiding behind math that none of have studued and therefore have no hope of understaning. It's not that hard (honest), it just involves a touch of lateral thinking.
  4. Standard memberFiathahel
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    23 Aug '03 18:51
    Originally posted by belgianfreak
    find the connection between these words:

    mug elf kid low wag age hop eat tag
    - they are all on the same line
    - they are all writen by belgianfreak
    - they all consist out of three letters (I personaly want to thank TheMaster37 for discovering that)
    and last but not least
    - they are all annoying me cause I can't see which connection is ment

    😕
  5. Standard memberroyalchicken
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    23 Aug '03 21:392 edits
    Originally posted by belgianfreak
    find the connection between these words:

    mug elf kid low wag age hop eat tag
    One could make each into a new word by adding an "s" at the beginning.

    Smug selves skid slowly and swag sage shop seat stags.
  6. Donationbelgianfreak
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    24 Aug '03 02:21
    Originally posted by royalchicken
    One could make each into a new word by adding an "s" at the beginning.

    Smug selves skid slowly and swag sage shop seat stags.
    thank you to the chicken with the correct answer. (porche en route)

    Was the puzzle appreciated or should I not post more?
  7. Standard memberroyalchicken
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    24 Aug '03 03:14
    By all means, keep posting. All puzzles are appreciated 🙂
  8. Standard memberFiathahel
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    24 Aug '03 09:52
    Yea, keep posting
  9. Standard memberTheMaster37
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    24 Aug '03 22:00
    Originally posted by belgianfreak
    bump

    come on people - are you only capable of hiding behind math that none of have studued and therefore have no hope of understaning. It's not that hard (honest), it just involves a touch of lateral thinking.
    There are at least two people here who study math...
  10. Standard memberroyalchicken
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    25 Aug '03 00:29
    And who might they be? If you're one, get a star and get in the Cult of Maths!
  11. Standard memberFiathahel
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    25 Aug '03 07:15
    Originally posted by royalchicken
    And who might they be? If you're one, get a star and get in the Cult of Maths!
    The Master and I both study math. (at least that's what we should do here instead of posting in the forums 🙂 )

    Perhaps now is a good time to become a member. Who doesn't want to be in the Cult of Maths. I haven't got a creditcard nor a us bank account though, so it might take some while.
  12. Standard memberroyalchicken
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    25 Aug '03 15:08
    What areas of math interest you in particular?
  13. Standard memberFiathahel
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    25 Aug '03 16:17
    Originally posted by royalchicken
    What areas of math interest you in particular?
    I'm interested in tha areas of financial mathematics, which is for the most part about stochastics. But also geometry interests me.

    Perhaps you know this. I've got a triangle ABC. On the line AB I take a point D, on BC I take E and on CA F. Show that if AE, BF, CD intersect in one point, AD/DB * BE/EC * CF/CA = 1.

    It is easy to prove for some special cases, but I can't do it in general.
  14. Donationrichjohnson
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    25 Aug '03 19:47
    Originally posted by Fiathahel
    I'm interested in tha areas of financial mathematics, which is for the most part about stochastics. But also geometry interests me.

    Perhaps you know this. I've got a triangle ABC. On the line AB I take a point D, on BC I take E and on CA F. Show that if AE, BF, CD intersect in one point, AD/DB * BE/EC * CF/CA = 1.

    It is easy to prove for some special cases, but I can't do it in general.
    I don't think that's true in the general case. If D's near B, E's near C and F's near A, then AE and CD intersect near C, and AE and BF intersect near A.
  15. Standard memberFiathahel
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    26 Aug '03 07:03
    Originally posted by richjohnson
    I don't think that's true in the general case. If D's near B, E's near C and F's near A, then AE and CD intersect near C, and AE and BF intersect near A.
    But then AD/DB * BE/EC * CF/FA =/= 1 .
    (I notice now I mistyped CF/FA the first time)

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