Yet Another...

Three people, Armand, Bela, and Cornelius, play a game wherein they roll one fair die in turns, in alphabetical order. Armand wins if he gets a 4,5, or 6. Bela wins by getting a 1 or a 2. Cornelius wins by getting a 3. If they take turns in the manner above, Armand rolling first, what is the probability that each will eventually win the game?

Armand - 9/13
Bela - 3/13
Cornelius - 1/13

Something like that?
Not quite sure if I got neither the problem nor the calculations right, though. It's pretty late here 🙂

Another quick check shows that it at least shouldn't be far from the truth 🙂

You are correct...good going 😀!

*sits down waiting for a new problem to show up in the thread list*

wouldnt the answer be out of 6?? like, 1/6, 2/6, 3/6? i dont see how its over 13...

It is the sum of an infinite geometric sequence of which the general term is either 1/2, 1/3, or 1/6 times 5/18 to some power.