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Posers and Puzzles

Posers and Puzzles

  1. Standard member royalchicken
    05 Jun '03 21:23
    Three people, Armand, Bela, and Cornelius, play a game wherein they roll one fair die in turns, in alphabetical order. Armand wins if he gets a 4,5, or 6. Bela wins by getting a 1 or a 2. Cornelius wins by getting a 3. If they take turns in the manner above, Armand rolling first, what is the probability that each will eventually win the game?
  2. 05 Jun '03 22:53
    Armand - 9/13
    Bela - 3/13
    Cornelius - 1/13

    Something like that?
    Not quite sure if I got neither the problem nor the calculations right, though. It's pretty late here
  3. 05 Jun '03 22:56
    Another quick check shows that it at least shouldn't be far from the truth
  4. Standard member royalchicken
    05 Jun '03 22:58
    You are correct...good going !
  5. 05 Jun '03 23:03
    *sits down waiting for a new problem to show up in the thread list*
  6. Donation astevenson
    i wish i was BOB!!!!
    06 Jun '03 19:04
    wouldnt the answer be out of 6?? like, 1/6, 2/6, 3/6? i dont see how its over 13...
  7. Standard member royalchicken
    06 Jun '03 19:31
    It is the sum of an infinite geometric sequence of which the general term is either 1/2, 1/3, or 1/6 times 5/18 to some power.