1. Standard memberroyalchicken
    CHAOS GHOST!!!
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    05 Jun '03 21:23
    Three people, Armand, Bela, and Cornelius, play a game wherein they roll one fair die in turns, in alphabetical order. Armand wins if he gets a 4,5, or 6. Bela wins by getting a 1 or a 2. Cornelius wins by getting a 3. If they take turns in the manner above, Armand rolling first, what is the probability that each will eventually win the game?
  2. Norway
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    05 Jun '03 22:53
    Armand - 9/13
    Bela - 3/13
    Cornelius - 1/13

    Something like that?
    Not quite sure if I got neither the problem nor the calculations right, though. It's pretty late here 🙂
  3. Norway
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    05 Jun '03 22:56
    Another quick check shows that it at least shouldn't be far from the truth 🙂
  4. Standard memberroyalchicken
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    05 Jun '03 22:58
    You are correct...good going 😀!
  5. Norway
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    05 Jun '03 23:03
    *sits down waiting for a new problem to show up in the thread list*
  6. Donationastevenson
    i wish i was BOB!!!!
    Larkfield!(kent, uk)
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    06 Jun '03 19:04
    wouldnt the answer be out of 6?? like, 1/6, 2/6, 3/6? i dont see how its over 13...
  7. Standard memberroyalchicken
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    06 Jun '03 19:31
    It is the sum of an infinite geometric sequence of which the general term is either 1/2, 1/3, or 1/6 times 5/18 to some power.
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