25 Aug '09 18:562 edits

r ——————>>Exp (ì w t) ———->> S=r Exp (ì wt) Nahhas’ Equation

Orbit——–>> Orbit light sensing——>> Visual Orbit; Exp = Exponential

Particle —->> light sensing of moving objects———— >> Wave

Newton———>>light sensing———->> Quantum

Quantum = Newton x Visual Effects

Quantum – Newton = Relativistic = Optical Illusions

E (Energy by definition) = mv²/2 = mc²/2; if v = c

m = mass; v= speed; c= light speed; w= angular velocity; t= time

S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects

P = visual velocity = change of visual location

P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t)

= (v + ì w r) Exp (ì w t) = v (1 + ì ) Exp (ì w t) = visual speed; v = wr

E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2

= m p²/2 = m v²/2 (1 + ì ) ² Exp (2ì wt)

= mv²/2 (2ì ) [cosine (2wt) + ì sine (2wt)]

=ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed

wt = π/2

E (visual) = ìmv² (1 – 2 + 0)

E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c

w t = π/4

E (visual) = imv² [1-1 +ỉ] =-mc²; v = c

wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 – ln2

Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)]

E (visual) = imv² (-ỉ/2) =1/2mc² v = c

Conclusion: E = mc² is the visual Illusion of E = mc²/2

PS: In case of E=mc² claims to be rest energy claims then

E=1/2m (m v + m’ r) ² = (1/2m) (m’ r) ²; v = 0

E = (1/2m) (mc) ²; m’ r =mc

E=mc²/2

Orbit——–>> Orbit light sensing——>> Visual Orbit; Exp = Exponential

Particle —->> light sensing of moving objects———— >> Wave

Newton———>>light sensing———->> Quantum

Quantum = Newton x Visual Effects

Quantum – Newton = Relativistic = Optical Illusions

E (Energy by definition) = mv²/2 = mc²/2; if v = c

m = mass; v= speed; c= light speed; w= angular velocity; t= time

S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects

P = visual velocity = change of visual location

P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t)

= (v + ì w r) Exp (ì w t) = v (1 + ì ) Exp (ì w t) = visual speed; v = wr

E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2

= m p²/2 = m v²/2 (1 + ì ) ² Exp (2ì wt)

= mv²/2 (2ì ) [cosine (2wt) + ì sine (2wt)]

=ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed

wt = π/2

E (visual) = ìmv² (1 – 2 + 0)

E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c

w t = π/4

E (visual) = imv² [1-1 +ỉ] =-mc²; v = c

wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 – ln2

Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)]

E (visual) = imv² (-ỉ/2) =1/2mc² v = c

Conclusion: E = mc² is the visual Illusion of E = mc²/2

PS: In case of E=mc² claims to be rest energy claims then

E=1/2m (m v + m’ r) ² = (1/2m) (m’ r) ²; v = 0

E = (1/2m) (mc) ²; m’ r =mc

E=mc²/2