22 Jul '13 15:50>5 edits
Is it possible to have a thin solid layer of mainly transparent material or optical filter that is, say, less than 1mm thick, that, ignoring any surface reflections (because can always use antireflective coatings ), selectively absorbs (and NOT reflects ) nearly all (say, more than 99% ) of an extremely narrow range of wavelengths of visible light (with a range of, say less than one nm difference in wavelength -so it is a very narrow absorption band ) while being virtually completely transparent (say, more than 99% transparency) to all other wavelengths of visible light?
To help answer this above question; can anyone give me ANY example at all of a pigment molecule that can be incorporated either into a solid transparent matrix or dissolved in a transparent liquid that would selectively absorb an extremely narrow range of visible light while being transparent to all other wavelengths?
Is it at least theoretically possible to fine-tine a semiconductor layer to do this?
I am not being lazy here; I have read:
http://en.wikipedia.org/wiki/Ultraviolet-visible_spectroscopy
http://en.wikipedia.org/wiki/Conjugated_system
http://en.wikipedia.org/wiki/Chromophore
-but don't see how any of that helps answer any of my questions.
I am also aware of UV filters that are transparent to all wavelengths of visible light but that is nothing like what I want here.
To help answer this above question; can anyone give me ANY example at all of a pigment molecule that can be incorporated either into a solid transparent matrix or dissolved in a transparent liquid that would selectively absorb an extremely narrow range of visible light while being transparent to all other wavelengths?
Is it at least theoretically possible to fine-tine a semiconductor layer to do this?
I am not being lazy here; I have read:
http://en.wikipedia.org/wiki/Ultraviolet-visible_spectroscopy
http://en.wikipedia.org/wiki/Conjugated_system
http://en.wikipedia.org/wiki/Chromophore
-but don't see how any of that helps answer any of my questions.
I am also aware of UV filters that are transparent to all wavelengths of visible light but that is nothing like what I want here.