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Originally posted by Nordlysthis has gone on and on, the problem is no one ever actually took the time to listen to my point...
I have never seen binary written backwards before. It normally works the same way as decimal, starting with the higher powers.
computers only understand boolean values (binary), it can only be on (1) on or (0) off... (true or false, or to be more precise, high and low voltage - with the 1 representing high)
my point was always that if you add a boolean value to 1 it still remains true, i.e. a 1... so 10 + 10 in binary will still be 10, a computer does not carry a number... this is boolean binary... my point was that you cannot say 10 + 10 = 100 in binary without specifying what form of binary you were using
to answer the other question, binary works backwards, highest first, so working in 8bit, you would have 128, 64, 32 16 8 4 2 1
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Originally posted by eatmybishopJust curious. Where did you learn this?
this has gone on and on, the problem is no one ever actually took the time to listen to my point...
computers only understand boolean values (binary), it can only be on (1) on or (0) off... (true or false, or to be more precise, high and low voltage - with the 1 representing high)
my point was always that if you add a boolean value to 1 it still r ...[text shortened]... binary works backwards, highest first, so working in 8bit, you would have 128, 64, 32 16 8 4 2 1
I have to believe that whatever you were taught was in a VERY limited context.
Originally posted by eatmybishopI see where you're coming from but unless you work in computers i don't really see how this is particularly useful,
this has gone on and on, the problem is no one ever actually took the time to listen to my point...
computers only understand boolean values (binary), it can only be on (1) on or (0) off... (true or false, or to be more precise, high and low voltage - with the 1 representing high)
my point was always that if you add a boolean value to 1 it still r ...[text shortened]... binary works backwards, highest first, so working in 8bit, you would have 128, 64, 32 16 8 4 2 1
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Originally posted by eatmybishoplol. Let me assure you that computers, in general, are more than capable of performing binary arithmetic (including carrying numbers) as well as performing boolean algebra. Now if you want to limit the context to boolean datatypes (which I suspect is your intent), then perhaps what you're saying may be true if you're also limiting discussion to specific hardware configurations. I have to say however that I wouldn't think that there'd be much practical value, in general, in performing binary arithmetic on boolean datatypes.
not to worry, the lightbulb has yet to turn on for you
So what exactly is the context in which you're operating?
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Originally posted by eatmybishopComptuers do carry numbers. It's called a shift-register.
this has gone on and on, the problem is no one ever actually took the time to listen to my point...
computers only understand boolean values (binary), it can only be on (1) on or (0) off... (true or false, or to be more precise, high and low voltage - with the 1 representing high)
my point was always that if you add a boolean value to 1 it still r ...[text shortened]... binary works backwards, highest first, so working in 8bit, you would have 128, 64, 32 16 8 4 2 1
Of course, computers don't ACTUALLY work in numbers at all. But if you design a physical system to have an abstract representation then the user can look at it as if such an interpretation were intrinsic, though it isn't.
Originally posted by orangutan01010111 01101000 01100001 01110100 00100000 01100001 01110010 01100101 00100000 01111001 01101111 01110101 00100000 01110111 01101111 01110010 01110010 01101001 01100101 01100100 00100000 01100001 01100010 01101111 01110101 01110100 00111111
01011001 01100101 01110011
01010110 01100101 01110010 01111001
Originally posted by SteinbergAnother interesting aspect is that so-called binary isn't actually represented by two voltage levels: a fairly wide range of voltage levels is recognized as "high" by the chips, and the same is true for "low", with a no-man's land in between (system reaction to which might be unpredictable), which is why voltage regulation is so important in solid state circuitry.
I see where you're coming from but unless you work in computers i don't really see how this is particularly useful,
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Originally posted by Mark AdkinsSo imagine what happens if, say, a moth gets into the works, or something like that, and its dead body creates a short and ends up turning what should be a "high" voltage input at some point into a "low" voltage input, or vice-versa, or takes what should be a "high" or "low" voltage input into a no-man's-land middle region which the system always or sometimes reacts erroneously to.
Another interesting aspect is that so-called binary isn't actually represented by two voltage levels: a fairly wide range of voltage levels is recognized as "high" by the chips, and the same is true for "low", with a no-man's land in between (system reaction to which might be unpredictable), which is why voltage regulation is so important in solid state circuitry.
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Originally posted by Mark Adkinssimple, put mothballs inside your computer case.😀
So imagine what happens if, say, a moth gets into the works, or something like that, and its dead body creates a short and ends up turning what should be a "high" voltage input at some point into a "low" voltage input, or vice-versa, or takes what should be a "high" or "low" voltage input into a no-man's-land middle region which the system always or sometimes reacts erroneously to.