Question about ratings on redhotpawn.com

Question about ratings on redhotpawn.com

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s

Joined
23 Jun 05
Moves
3583
27 Jun 05

What happens if a provisionally ranked 1200 player draws with another provisionally ranked 1200 player in a rated game?

Will either rating change after the game?

Force of Nature

The Bathroom

Joined
12 May 05
Moves
31388
27 Jun 05

Originally posted by skims
What happens if a provisionally ranked 1200 player draws with another provisionally ranked 1200 player in a rated game?

Will either rating change after the game?
I have no clue. Why don't you try it yourself.

B
Non-Subscriber

RHP IQ

Joined
17 Mar 05
Moves
1345
03 Jul 05

Now we know the answer.

Force of Nature

The Bathroom

Joined
12 May 05
Moves
31388
03 Jul 05

Originally posted by Bowmann
Now we know the answer.
Go play in someone else's sandbox.

B
Non-Subscriber

RHP IQ

Joined
17 Mar 05
Moves
1345
03 Jul 05

Originally posted by Wildfire
Go play in someone else's sandbox.
That reminds me, when's Katty due back?

N

Joined
07 Jan 05
Moves
20117
04 Jul 05

meeuw!

DS
I'm A Mighty Pirateā„¢

PaTROLLING the forum

Joined
01 Dec 04
Moves
36332
04 Jul 05

Originally posted by Bowmann
That reminds me, when's Katty due back?
Why, you fed up chasing cars and p*ss*ng on trees already so you need your favourite leg to hump?

I

Joined
18 Jun 05
Moves
6610
06 Jul 05

If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
= 1200 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

X
Cancerous Bus Crash

p^2.sin(phi)

Joined
06 Sep 04
Moves
25076
06 Jul 05

Originally posted by Invader
If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
...[text shortened]... 0 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

The win expectancy formula is used when you have played more than 20 games (your rating isn't provisional anymore).

Until you complete 20 games (and you've completed more than 5) your rating is the average of all your game values.
The game value is your opponent's rating + 400 if you win , -400 if you lose. It's equal to your opponent's rating if you draw.
If your opponent is provisional the 400s are 200s.

Therefore if two p1200's play each other and draw no change is made to their ratings.

F

Joined
24 May 05
Moves
1958
06 Jul 05

Originally posted by Invader
If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
...[text shortened]... 0 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

what's 'K'?
is it always 32?

X
Cancerous Bus Crash

p^2.sin(phi)

Joined
06 Sep 04
Moves
25076
06 Jul 05

Originally posted by Florrat
what's 'K'?
is it always 32?
Read the FAQ, it has a detailed breakdown for the rating calculation:

"K is a constant (32 for 0-2099, 24 for 2100-2399, 16 for 2400 and above)"

The numbers are your rating.