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Question about ratings on redhotpawn.com

Question about ratings on redhotpawn.com

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What happens if a provisionally ranked 1200 player draws with another provisionally ranked 1200 player in a rated game?

Will either rating change after the game?

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Originally posted by skims
What happens if a provisionally ranked 1200 player draws with another provisionally ranked 1200 player in a rated game?

Will either rating change after the game?
I have no clue. Why don't you try it yourself.

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Now we know the answer.

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Originally posted by Bowmann
Now we know the answer.
Go play in someone else's sandbox.

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Originally posted by Wildfire
Go play in someone else's sandbox.
That reminds me, when's Katty due back?

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meeuw!

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Originally posted by Bowmann
That reminds me, when's Katty due back?
Why, you fed up chasing cars and p*ss*ng on trees already so you need your favourite leg to hump?

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If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
= 1200 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

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Originally posted by Invader
If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
...[text shortened]... 0 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

The win expectancy formula is used when you have played more than 20 games (your rating isn't provisional anymore).

Until you complete 20 games (and you've completed more than 5) your rating is the average of all your game values.
The game value is your opponent's rating + 400 if you win , -400 if you lose. It's equal to your opponent's rating if you draw.
If your opponent is provisional the 400s are 200s.

Therefore if two p1200's play each other and draw no change is made to their ratings.

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Originally posted by Invader
If you have less than 5 games, no. Otherwise I have attepted the math:

K=32

Old Rating=1200

Score = .5

Win Expectancy = 1 / (10^((OpponentRating-YourRating)/200)+1)
= 1 / (10^((1200-1200/200)+1)
= 1 / (10^1)
= 1 / 10
= .1

New Rating = Old Rating + K * (Score - Win Expectancy)
...[text shortened]... 0 + 32 * (.5 - .1)
= 1200 + 32 * .4
= 1200 + 12.8
= 1213

what's 'K'?
is it always 32?

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Originally posted by Florrat
what's 'K'?
is it always 32?
Read the FAQ, it has a detailed breakdown for the rating calculation:

"K is a constant (32 for 0-2099, 24 for 2100-2399, 16 for 2400 and above)"

The numbers are your rating.

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