1 edit
Originally posted by schakuhrThat's 8-5 in points. The one starting this thread is 4-0.
[fen]8/6P1/3b4/6P1/1k6/4r3/2B5/1K6[/fen]
black to move
this is a pretty lopsided draw too.
Still, as someone else posted, I didn't think about the K+ 2 knights vs. king, where there's no forced mate. That's a 6 point advantage with no forced win, so I guess that's the most lopsided draw possible.
They say it's possible to force mate with a Bishop and a knight vs. a king. I guess it must be, but for the life of me, I can't figure out how to do it.
Originally posted by kbaumenIt was mainly a joke in response to schakuhr's problem [which depended much more on tactics than general principles] with a pinch of morbid curiousity [what is the maximum material deficit that can yield a drawn position? The only thing I did not do is promote all the pawns to Q.]
What's the idea behind this? To prove that white can draw with king and bishop against a whole set?
1 edit
Originally posted by SwissGambitI wonder what the moves could be... 😉 Unless of course cxb8=N??
And finally,
***The most ridiculously lopsided draw possible in the game of chess***
[fen]1r1kb1rq/8/2PK1bqq/8/n4n1q/6q1/5q1q/5qq1 w - - 0 1[/fen]
White to move
White, materially at a 1 to 103 point disadvantage, escapes with a draw.
Originally posted by sh76Um, the solution was intended to be obvious. That was the joke. 😉 🙂
1. c7+ Kc8 (forced)
2. cxb8=Q Kxb8 (forced)
stalemate
Still, I think the topic of this post was more about material draws, not stalemates or perpetual checks, for which, of course, material disparity is basically irrelevant.
Originally posted by sh76Well, if there's anything I hate, it's people who can't stick to the topic. 😛
1. c7+ Kc8 (forced)
2. cxb8=Q Kxb8 (forced)
stalemate
Still, I think the topic of this post was more about material draws, not stalemates or perpetual checks, for which, of course, material disparity is basically irrelevant.