14 knights

Place 14 knights on the chessboard, so all the empty squares - and ONLY the empty squares - will be attacked.

Hmm, I can do it with 16 :p

Originally posted by TheMaster37
Hmm, I can do it with 16 :p

Originally posted by metbierop
so you can't do it with 14?

Where did you get 16 knights from... do you own a chess set shop?

Originally posted by Griddle
Where did you get 16 knights from... do you own a chess set shop?

This can also be done with 8 queens. But it's a tad easier.

Originally posted by Obese
This can also be done with 8 queens. But it's a tad easier.

I'm not sure I understand the puzzle.

The statement of the problem is simple. Place 14 knights on the board in such a way that it meets 2 qualifications.

1 All squares where a knight is not have a knight attacking/defending them.
2 No square with a knight is attacked or defended by a fellow knight.
3 Presumably, no square has more than 1 knight..

I note one thing in particular. There is nothing prohibiting 2 or more knights from attacking/defending the same square, only each other. And that is probably key.

16 isn't too terribly hard. 14 seems like not quite enough, especially if you're trying to patch them in..

I always end up with 2 uncovered squares.. Is there a solution?

Originally posted by geepamoogle
16 isn't too terribly hard. 14 seems like not quite enough, especially if you're trying to patch them in..

I always end up with 2 uncovered squares.. Is there a solution?

I've done it with twelve but have four spaces left which i have to fill up with knights. So that makes 16. I can't do it any better than that

Originally posted by XanthosNZ
[fen]5n1n/2n5/2nn3n/7n/n7/4nn2/5n2/nnn5[/fen]

I can do this, simpler than wot evry1 els has done n do it with queens with only 6

Knights

= G 3,5,6 F 3,5,6 E1 D1 C 3,5,6 B 3,5,6


Queens

= The middle four and A6 n F1 i tink