1. santa cruz, ca.
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    20 Jun '14 14:325 edits
    how many numbers in succession starting with zero can anyone do?
    post you solutions
    can anyone do the fist 15 or more?

    +, -, x, /, (), ^, log, square roots, decimal points, factorials, double factorial, etc. are a few math symbols that can be used

    Good luck!
  2. SubscriberPonderable
    chemist
    Linkenheim
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    20 Jun '14 15:22
    Originally posted by lemondrop
    how many numbers in succession starting with zero can anyone do?
    post you solutions
    can anyone do the fist 15 or more?

    +, -, x, /, (), ^, log, square roots, decimal points, factorials, double factorial, etc. are a few math symbols that can be used

    Good luck!
    (4+4)-(4-4)=0 that was easy...
  3. santa cruz, ca.
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    20 Jun '14 15:281 edit
    (4+4)-(4-4)=8
    sorry ponderable

    (4+4)=8
    (4-4)=0
    8-0=8
  4. Standard memberforkedknight
    Defend the Universe
    127.0.0.1
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    20 Jun '14 16:541 edit
    4!/sqrt(4) + 4/4 = 13
  5. santa cruz, ca.
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    20 Jun '14 17:023 edits
    works for me
    good job

    4!=24
    sqrt of 4=2
    4/4=1
    24/2=12 +4/4=1
    12+1=13

    anyone with a different solution?
  6. Standard memberAThousandYoung
    or different places
    tinyurl.com/2tp8tyx8
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    20 Jun '14 18:072 edits
    Now we need 11...
  7. santa cruz, ca.
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    20 Jun '14 20:00
    11 is not that difficult
    hint: use the square root function
  8. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    20 Jun '14 20:52
    Originally posted by Ponderable
    (4-4)*4+4=4
    To be clear, it should be ((4-4)*4)+4=4
  9. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    20 Jun '14 20:574 edits
    Originally posted by forkedknight
    4+(4-4)/4 = 4
    4 + (4/4)^4 = 5
    (4 + 4)/4 + 4 = 6
    You need to get the parenthesis stuff right to be accurate, your (4+4)/4+4 could be taken as zero as it stands.

    To be accurate you need (((4+4)/4)+4)=6.

    or ((4+4)/4)+4=6, a bit simpler but it does come out as 6 as written, on my casio calculator.

    The first example, 4+(4-4) could be taken as 4 then divide by 4 would be 1 if not clarified by parentheses, but as you wrote it, my calculator brings it out as 4.

    .
  10. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    20 Jun '14 21:12
    Originally posted by lemondrop
    4+(4-4)/4=1 not 4
    your equation for the number 5 is also incorrect
    He is getting those results running it through a Casio calculator or some other brand that uses the order rules. It comes out as four running through a casio.

    It still can be taken as 1 by someone not following the same order rules.

    I think it should be given with proper parentheses to eliminate such confusion.
  11. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    20 Jun '14 21:282 edits
    Originally posted by forkedknight
    4!/sqrt(4) + 4/4 = 13
    If you do the math first, it works but I cannot enter it as shown on my casio calculator.

    On my TI84 it doesn't seem to have a factorial function so I have to do it this way🙁(4*3*2)/(sqr(4))+(4/4) to get 13 which is cheating🙂

    You could write a user defined program as a factorial and use that instead I guess. Surprised they didn't include factorial on the TI84.

    I'll try it on my trusty rusty HP48, see what I get in reverse polish. Don't have time right now.
  12. santa cruz, ca.
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    20 Jun '14 22:12
    parentheses are absolutely necessary to avoid any ambiguity
  13. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    21 Jun '14 13:093 edits
    Originally posted by lemondrop
    parentheses are absolutely necessary to avoid any ambiguity
    For sure! Otherwise there can by several interpretations of the outcome.

    Like 4^4+4/4, is that 257 or 65?

    If you want the outcome to be 65, you go (4^4+4)/4 (4^4=256 plus 4=260 /4 =65

    If you want it to be outcome to be 257 you go (4^4)+(4/4) 4^4=256 plus 4/4, (1)=257.

    Everyone needs to get up to speed on this issue.
  14. santa cruz, ca.
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    21 Jun '14 16:55
    so far we have:
    0=44-44
    1=44/44
    2=(4x4)/(4+4)
    3=(4x4-4)/4
    4=(4x4)/((sqrt(4)+sqrt(4))

    5=4+(4/4)^4
    6=(4+4)/4+4
    7=44/4-4
    8=4-4+4+4
    9=4+4+(4/4)
    10=4+4+4-sqrt4
    11=
    12=4(4-4/4)
    13=4!/sqrt(4)+4/4
  15. santa cruz, ca.
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    21 Jun '14 16:56
    11 is open for a solution
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