Originally posted by crazyblue
Long time ago I came up with a puzzle which I could never solve somehow. Now I remembered it again, so maybe someone here knows how to do it? I think I'll give it another try too...
On a racing track (6.9 km length) three vehicles run with constant speed. Michael Schumachers Ferrari runs with constant 290 km/h, a Ford KA runs with 130 km/h and I ride ...[text shortened]... again?
b) When (time and lap) will we all be at the start/finish line at the same time again?
well the fastest car, 290 kliks makes 1008.695652 laps/day
the B car 130 kliks makes 452.173913 L/D
and the moped makes 243.4782608 L/D.
you multiplly all three L/D #'s to get 111,051,861.5 days
which is 304,043 years, 5 months, 2 days, 50 minutes and 0.384 seconds which seems to be when they will all line up at the starting
line again. Of course we are ignoring the differance in inner track
length vs. track outer edge, which are differant lengths.