Originally posted by FiathahelAccording to Wikipedia (http://en.wikipedia.org/wiki/Alkane), the generic formula for acyclic alkanes is C(n)H(2n+2).
How many different alkanes are there with n carbon atoms.
Alkane: a collection carbon atoms, with the property that a carbon atom is connected with at least one and up to four other carbon atoms and has no cykels.
According to the definition, there can only be exactly one alkane (by definition) for each n, so I would conclude that the answer to your question is 1.
-Ray.
Originally posted by rgoudieI do no know what you mean with C(n)H(2n+2)
According to Wikipedia (http://en.wikipedia.org/wiki/Alkane), the generic formula for acyclic alkanes is C(n)H(2n+2).
According to the definition, there can only be exactly one alkane (by definition) for each n, so I would conclude that the answer to your question is 1.
-Ray.
Their are more than one alkanes possible with n C-atoms. for example with n = 4:
C-C-C-C
and
C
|
C-C
|
C
Originally posted by FiathahelIs
I do no know what you mean with C(n)H(2n+2)
Their are more than one alkanes possible with n C-atoms. for example with n = 4:
C-C-C-C
and
C
|
C-C
|
C
//////C///
//C///C///
C C C C C
//C///C///
//C///////
different from
//C///C///
C C C C C
//C///C///
//C///C///
? (The slashes are for spacing purposes)
Originally posted by AcolyteNo, that is the same.
Is
//////C///
//C///C///
C C C C C
//C///C///
//C///////
different from
//C///C///
C C C C C
//C///C///
//C///C///
? (The slashes are for spacing purposes)
It is difficult to draw them here, but If you mean that there are 4 C's in the 2nd column and 4 in the 4th it is also the same as
//C///C///
C C C C C C
//C///C///
//C///////
You should see them as a 3D object that can twist in every direction.
Originally posted by FiathahelAh, that makes things easier. It means you can see an n-alkane as a relation ~ on the set {1,...,n} with the following properties:
No, that is the same.
It is difficult to draw them here, but If you mean that there are 4 C's in the 2nd column and 4 in the 4th it is also the same as
//C///C///
C C C C C C
//C///C///
//C///////
You should see them as a 3D object that can twist in every direction.
~ is symmetric and antireflexive
The 'edges' (x,y) where x~y form a tree connecting the whole set
Given any x, the number of y for which x~y is <5
Two relations are equivalent iff they can be mapped to each other by permutation of the set.
Originally posted by iamatigerNot in the light of Fiathahel's example. If you picture the molecule as balls connected by sticks, both the balls and the sticks can be twisted as much as you like.
although
- - - c - - - -
c c c c c c c c
- - - c - - - -
- - - c - - - -
is different from
- - c - - - -
c c c c c c c
- - c - - - -
- - c - - - -
- - c - - - -
Originally posted by AcolyteI don't think that's always true. Some molecules, known as "chiral" molecules or "stereoisomers" can have different properties than their mirror image.
Not in the light of Fiathahel's example. If you picture the molecule as balls connected by sticks, both the balls and the sticks can be twisted as much as you like.
(i.e.:
/////D
/////|
A---C---B
/////|
/////E
is different than:
/////E
/////|
A---C---B
/////|
/////D)
Originally posted by richjohnsonThat's why I asked. I think for the purposes of this puzzle we are to ignore chirality.
I don't think that's always true. Some molecules, known as "chiral" molecules or "stereoisomers" can have different properties than their mirror image.
(i.e.:
/////D
/////|
A---C---B
/////|
/////E
is different than:
/////E
/////|
A---C---B
/////|
/////D)
We can draw any alkane from ethane upwards like this:
...../P'
C-C-Q'
.....\R'
where the Cs are carbon atoms, and P', Q' and R' are collections of carbon atoms (possibly empty) such that P = C-P', Q = C-Q' and R = C-R' are alkanes. Let P, Q and R be p-,q- and r-alkanes respectively. Then p+q+r = n+1, where n is the number of carbon atoms in the whole thing. The way I've done things p,q and r could be 1,2,3,4,5...., but given n we must have p between 1 and n-1, q between 1 and n-p and r = n+1-p-q.
Two porblems arise with trying to do an induction on this basis. Firstly we don't care about the order of p,q and r, but that's easily fixed; more seriously, given an alkane, the choice of start atom (the C on the left of the diagram) is arbitrary, aside from the insistence that it only connects to one other carbon atom (such an atom must exist for ethane or bigger, as alkanes have no cycles), and the same alkane could have representations which look different from each other by choosing a different start atom. Can anyone think of a better representation that deals with this second issue?