1. Joined
    26 Apr '03
    Moves
    26771
    18 Feb '04 20:062 edits
    Originally posted by Acolyte
    We can draw any alkane from ethane upwards like this:

    ...../P'
    C-C-Q'
    .....\R'

    where the Cs are carbon atoms, and P', Q' and R' are collections of carbon atoms (possibly empty) such that P = C-P', Q = C-Q' and R = C-R' are ...[text shortened]... hink of a better representation that deals with this second issue?
    I think the "enumeration of alkanes" is a hard problem with no mathematically derivable and absolutely correct solution.

    A counting scheme with some duplicates, would be to represent each alkane as an integral number of repeats of the following unit:

    .a.
    -c-
    .b.

    where the number of repeates is the order of the alkane, and a and b are alkanes of lesser order. The zeroth alkane is defined as a single hydrogen atom

    then the number of alkanes of each order follow the sequence
    order1 = 1
    order2 = (order1)^4
    order3 = ((order2)+(order1))^6
    order4 = ((order3)+( order2)+(order1))^8


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