Bishops

Originally posted by LivingLegend
White: Bishops from a1 till h1, b2-g2, c3-f3, d4-e4

Black: b8-g8, c7-f7, d6-e6!

14 would be true if white couldn't attack white...the riddle was the white just couldn't attack black!

Olav

Sorry but you miss understood white can't attack black or white, & black can't attack white or black, in fact the colour of the bishops does not matter.

Furthermore, and this may come as a bit of a shock to some of you, 14 isn't the answer either!

Keep on trying.....

Also regarding the queens 8 is wrong too!
🙄

8 queens is fully possible.

Originally posted by zamba
8 queens is fully possible.

Nope it is not right.
I'll send you over a special clue if you promise not to tell anybody else ?

8 queens is possible, as evidenced by the earlier thread 'eight queens'.

Oh. I didn't know about that previous post.

However:
a6, b1, c5, d2, e8, f3, g7, h4.

Originally posted by zamba
Oh. I didn't know about that previous post.

However:
a6, b1, c5, d2, e8, f3, g7, h4.

However the question on this thread is slightly different so answer is not quite the same!😲

I can only fit 14 on as well.
8 down one side of the board, 6 on the other side. Don't know how to fit any more on there.

And yes, 8 queens is the maximum amount of queens you can fit on a board without any one attacking another.

Originally posted by Jay Peatea
What is the maximum number of bishops you can put on a chess board before one of them is able to take another bishop?

14 bishops can go on board before any attacks another

thus 15 bishops is themaximimum point where it's possible that last bishop placed on board is first bishop to attack another bishop


same logic with queen

8 queens is maximum number of queens to be placed on board with none attacking each other so the 9th queen fits your logic here like the bishops

Originally posted by villa68
14 bishops can go on board before any attacks another

thus 15 bishops is themaximimum point where it's possible that last bishop placed on board is first bishop to attack another bishop


same logic with queen

8 queens is maximum number of queens to be placed on board with none attacking each other so the 9th queen fits your logic here like the bishops

Haha, he fooled us all, (except you...😀) nice riddle!

Olav

Originally posted by villa68
14 bishops can go on board before any attacks another

thus 15 bishops is themaximimum point where it's possible that last bishop placed on board is first bishop to attack another bishop


same logic with queen

8 queens is maximum number of queens to be placed on board with none attacking each other so the 9th queen fits your logic here like the bishops

10 out of 10 for effort, but these arn't the right answer either. Any more takers ?
😉

Originally posted by Jay Peatea
10 out of 10 for effort, but these arn't the right answer either. Any more takers ?
😉

You can't be serious! Give us the answers!

Olav

Originally posted by LivingLegend
You can't be serious! Give us the answers!

Olav

Lateral thinking is what is needed to solve this riddle ! Still if you promise not to tell I'll send you the answer just so that you know that there is a proper solution.😀

Originally posted by Jay Peatea
Lateral thinking is what is needed to solve this riddle ! Still if you promise not to tell I'll send you the answer just so that you know that there is a proper solution.😀

I can get 32 bishops on the board without any of them being able to attack another bishop, as long as I've got at least 24 pawns to protect them. 😉

Originally posted by richjohnson
I can get 32 bishops on the board without any of them being able to attack another bishop, as long as I've got at least 24 pawns to protect them. 😉

We have a winner.

The correct answers are 32 for the bishops e.g. 4 rows of bishops separated by 4 rows of pawns (this being the simplest pattern although there are others) & 16 Queens each one separated by a wall pawns

Welldone
😀