Originally posted by royalchickenLOL!! It is the same answer. The water level wouldn't change until you got back on land. The bowling ball becomes superfluous.
Well, I'm in the boat before and after, so it shouldn't have any effect. Although if you like, I am 116 pounds and about the same density as water
Or if you like assume that the ball goes into the boat, which gets shoved into the middle of the lake, then the ball rolls out.
Originally posted by royalchickenWell, if we take you out of the boat all together.....whose going to row it? Just kidding....I would say that: 1) When the ball gets on the boat the water level rises; and, 2)when it falls off the boat (perhaps through third party levitation ) the water level stays the same. Is this also incorrect?
I meant (again...explanation is apparently not my bag ) that I'm not in the boat at all.
Originally posted by royalchickenIt's been quite a while since I was in any kind of science class; but, it seems to me that it has to do with density, not size.
The first is correct. The ball is displacing its weight. But when it falls in, does the water (third party ) care how heavy it is, or just how big?
Originally posted by royalchickenJust a thought, but it would seem that, being a solid, the ball by definition would have to be denser than water, which as we know is a liquid.
Right. Density is the amount of mass per unit of volume (size). So the mass of the ball displaces water in the boat....but what about out of the boat? Is the ball denser than water?