Originally posted by skeeter
Too easy. Juggle the stones as he crosses the bridge. At any one moment he will only be holding two stone's as the other will always be in the air
I refute this classic answer!
He is still supporting the three stones. To toss one stone up in the air requires some momentum, whch requires force, which requires work. Thus, this extremely-light
Indiana Jones must use more force against each tossed stone than he would otherwise use supporting it in his hand through the same distance. I'm fairy certain that the amount of work is almost the same in both situations. That is, I suspect that the amount of work required to toss a stone in the air for one second is very close to the amount of work required to carry the same stone for one second. Also, at the same time, when a different stone falls, Indiana must catch the stone and absorb its downward momentum. All this extra force presses him down against the rope with as much extra force as if
he was imply carrying them in his hands.
In physics, it would seem that you don't get anything for nothing.