1. Joined
    26 Apr '03
    Moves
    26771
    09 Oct '10 08:51
    I have a regular decagon, and inside it I have drawn the largest square that will fit.

    What it the ratio:

    Area_Of_Square / Area_of_Decagon
  2. ALG
    Joined
    16 Dec '07
    Moves
    6190
    09 Oct '10 12:15
    0,6639
  3. ALG
    Joined
    16 Dec '07
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    6190
    09 Oct '10 13:27
    Originally posted by Thomaster
    0,6639
    No, that must be wrong.
  4. Joined
    11 Nov '05
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    43938
    09 Oct '10 16:101 edit

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  5. Joined
    26 Apr '03
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    26771
    10 Oct '10 21:30
    Originally posted by Thomaster
    No, that must be wrong.
    Yes, I think it is wrong too, but quite close.
  6. ALG
    Joined
    16 Dec '07
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    6190
    10 Oct '10 21:36
    Originally posted by iamatiger
    Yes, I think it is wrong too, but quite close.
    That is because my square was a diamont.
  7. Joined
    26 Apr '03
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    26771
    11 Oct '10 07:34
    Originally posted by Thomaster
    That is because my square was a diamont.
    Ah, yes. I got a diamond at first too.
  8. Joined
    07 Sep '05
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    35068
    11 Oct '10 11:481 edit
    Are you sure? I'm probably missing something, but I got the same answer with something that I'm pretty sure is a square. (Though I'm not certain it's the largest square, admittedly).

    Presumably that 0.6639 is an approximation of (cos 9)^2/(5 sin 18 cos 18)
  9. Joined
    07 Sep '05
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    35068
    11 Oct '10 13:49
    To provide more detail, my "quadrilateral" is constructed as follows:

    If the decagon has a vertex at 0 degrees (and 36, 72, etc), then the square has vertices at 9, 99, 189, 279 degrees.

    If the answer isn't right, where I went wrong must be:
    - that isn't a square
    - that isn't the largest square
    - miscalculating the areas

    Which is it?
  10. Joined
    26 Apr '03
    Moves
    26771
    12 Oct '10 00:515 edits
    Originally posted by mtthw
    If the answer isn't right, where I went wrong must be:
    - that isn't a square
    - that isn't the largest square
    - miscalculating the areas

    Which is it?
    I think you miscalculated the areas, unless I'm wrong (The fourth possibility!).
  11. Joined
    07 Sep '05
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    35068
    12 Oct '10 09:33
    Originally posted by iamatiger
    I think you miscalculated the areas, unless I'm wrong (The fourth possibility!).
    OK, I'll have another look at it later. Ta.
  12. Joined
    07 Sep '05
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    35068
    12 Oct '10 10:531 edit
    <slaps head/>

    Silly mistake 🙂.

    0.6310 any closer?
  13. Joined
    26 Apr '03
    Moves
    26771
    12 Oct '10 20:16
    Originally posted by mtthw
    <slaps head/>

    Silly mistake 🙂.

    0.6310 any closer?
    Now only the 4th decimal place is wrong I think.

    Can you give your expression for the answer?
  14. Joined
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    35068
    13 Oct '10 08:421 edit
    Originally posted by iamatiger
    Now only the 4th decimal place is wrong I think.

    Can you give your expression for the answer?
    I get:

    cos 18/(5 sin 18 cos^2 9)

    = 0.6309778... = 0.6310 to 4 d.p. (according to this calculator 🙂)
  15. ALG
    Joined
    16 Dec '07
    Moves
    6190
    19 Oct '10 14:571 edit
    1 / (20 × sqrt( 5 + 2sqrt(5)) × sin² 9) = 0,6639

    Same answer. 😳
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