02 Dec '10 21:23>24 edits
Sorry I forgot about this
you are both still slightly wrong:
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so the answer is:
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you are both still slightly wrong:
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From the wikipedia entry on decagons:
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Area of a regular decagon = 2.5dt where:
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t = length of a side
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d = distance between two parallel sides
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they are related:
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d = 2t(cos(54) + cos(18)) {angles in degrees}
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so area_of_decagon = 5t^2(cos(54) + cos(18))
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lets say the side is length one, then:
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area 5(cos(54) + cos(18))
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Now a decagon has 10 sides, and a square has 4, so there should be 2.5 decagagon sides between any two square corners. Draw a decagon.
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Try setting a square corner to be a decagon corner,
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now drawing corners at
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2.5 side spacings we see that even though the sides are the
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same length, the diagonals of the "square" are different lengths
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so it isnt actually a square
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Shunt every square corner round
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by a quarter of a side, and we can see that all the diagonals
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will now be the same, and the sides are the same, so its a square.
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By pythagoras its easy to see that the length of a diagonal
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of this square is
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sqrt(d^2 + (t/2)^2)
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where d and t are as above
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the area of a square, in terms of its diagonal length is:
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diagonal_length^2/2
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so the area of the square is:
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d^2/2 + t^2/8
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recalling that d = 2t(cos(54) + cos(18)) {angles in degrees} and that t = 1
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area_of_square = 2(cos(54) + cos(18))^2 + 1/8
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so the ratio:
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square_area/decagon_area
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(2(cos(54) + cos(18))^2 + 1/8)/5(cos(54) + cos(18))
so the answer is:
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0.6317826922466960