1. Joined
    26 Apr '03
    Moves
    26771
    02 Dec '10 21:2324 edits
    Sorry I forgot about this

    you are both still slightly wrong:

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    From the wikipedia entry on decagons:

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    Area of a regular decagon = 2.5dt where:

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    t = length of a side

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    d = distance between two parallel sides

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    they are related:

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    d = 2t(cos(54) + cos(18)) {angles in degrees}

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    so area_of_decagon = 5t^2(cos(54) + cos(18))


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    lets say the side is length one, then:

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    area 5(cos(54) + cos(18))


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    Now a decagon has 10 sides, and a square has 4, so there should be 2.5 decagagon sides between any two square corners. Draw a decagon.


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    Try setting a square corner to be a decagon corner,

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    now drawing corners at

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    2.5 side spacings we see that even though the sides are the

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    same length, the diagonals of the "square" are different lengths


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    so it isnt actually a square


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    Shunt every square corner round

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    by a quarter of a side, and we can see that all the diagonals

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    will now be the same, and the sides are the same, so its a square.


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    By pythagoras its easy to see that the length of a diagonal

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    of this square is

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    sqrt(d^2 + (t/2)^2)


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    where d and t are as above


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    the area of a square, in terms of its diagonal length is:

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    diagonal_length^2/2


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    so the area of the square is:

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    d^2/2 + t^2/8


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    recalling that d = 2t(cos(54) + cos(18)) {angles in degrees} and that t = 1


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    area_of_square = 2(cos(54) + cos(18))^2 + 1/8


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    so the ratio:

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    square_area/decagon_area


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    (2(cos(54) + cos(18))^2 + 1/8)/5(cos(54) + cos(18))


    so the answer is:
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    0.6317826922466960
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