1. my head
    Joined
    03 Oct '03
    Moves
    671
    21 Jan '05 21:50
    0=0
    (x+y)(x-y)=(x+y)(x-y)
    (x+y)(x-y)=x^2-y^2
    (x-y)(1+dy/dx)+(x+y)(1-dy/dx)=2x-2y(dy/dx)
    x+x(dy/dx)-y-y(dy/dx)+x-x(dy/dx)+y-y(dy/dx)=2x-2y(dy/dx)
    2x-2y(dy/dx)=2x-2y(dy/dx)
    0=0

    damn!
  2. Standard memberneight
    Cheese log/Beef log
    Joined
    27 Oct '04
    Moves
    4853
    21 Jan '05 22:29
    what exactly are you trying to show?
  3. Standard memberTheMaster37
    Kupikupopo!
    Out of my mind
    Joined
    25 Oct '02
    Moves
    20443
    23 Jan '05 14:15
    That equations don't all hold with derivatives?
  4. my head
    Joined
    03 Oct '03
    Moves
    671
    25 Jan '05 15:081 edit
    clearly one can write an "equation" in which all variables will cancle, but:

    can you make an equation in which all variables will cancle, but of which one can find the deriviative?

    i haven't learned integrals (anit-derivatives) yet, but are they any use here?

    it's a bit complex what i'm looking for here, so just show anything you find.
  5. Joined
    26 Apr '03
    Moves
    26771
    25 Jan '05 18:26
    That would be like saying
    x=x
    and then trying to find the rate of change of x
  6. Standard memberXanthosNZ
    Cancerous Bus Crash
    p^2.sin(phi)
    Joined
    06 Sep '04
    Moves
    25076
    25 Jan '05 18:28
    Originally posted by iamatiger
    That would be like saying
    x=x
    and then trying to find the rate of change of x
    Is it x?
  7. Hawaii
    Joined
    13 Jan '05
    Moves
    41604
    26 Jan '05 02:27
    Originally posted by fearlessleader
    clearly one can write an "equation" in which all variables will cancle, but:

    can you make an equation in which all variables will cancle, but of which one can find the deriviative?

    i haven't learned integrals (anit-derivatives) yet, but are they any use here?

    it's a bit complex what i'm looking for here, so just show anything you find.
    If all the variables cancel, you do not have an equation, only a statement. yx=yx is not an equation because there is no parameters for the variables to fall into, an so belong to an endless set, and so one cannot find the derivative for the equation as the derivative is a rate of change for a varible. No parameters = no definition of the varibles change.
Back to Top

Cookies help us deliver our Services. By using our Services or clicking I agree, you agree to our use of cookies. Learn More.I Agree