1. Standard memberAgerg
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    13 Sep '09 12:26
    I know four fours have been done here (not sure about 5 5s though)
    You have to form the numbers from 0-whatever (in ascending order) using simple arithmetic operations. These being:

    addition +
    subtraction -
    multiplication *
    division /
    factorial !
    concatenation (eg: 55 or.55 etc...)
    decimals . (ie .5)
    recurring decimals (no overbar (or underline) so will let .5 denote .555555.... = 5/9)
    square roots sqrt() (debatable because of implied 1/2 but then factorial has implied 2,3,4 in it yet no-one says anything about that)
    exponentiation ^

    Also since the first 30 or so are trivial should we start a bit later?
  2. Sigulda
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    13 Sep '09 15:28
    5!/5 + 5 + 5/5 = 30
    5*5 + 5 + 5/5 = 31
    Hmmm...... = 32
    5.5 * 5 + 5.5 = 33
    5!/5 + sqrt(5)*sqrt(5) + 5 = 34
    5(5 + 5/5) + 5 = 35

    LaTeX would make this forum much nicer, though it's not that easy to implement probably.
  3. Standard memberAgerg
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    13 Sep '09 15:405 edits
    Originally posted by Kristaps
    5!/5 + 5 + 5/5 = 30
    5*5 + 5 + 5/5 = 31
    Hmmm...... = 32
    5.5 * 5 + 5.5 = 33
    5!/5 + sqrt(5)*sqrt(5) + 5 = 34
    5(5 + 5/5) + 5 = 35

    LaTeX would make this forum much nicer, though it's not that easy to implement probably.
    Yeah I agree with you about the LaTeX...the boldface for recuring .5... looks crappy!
    ((sqrt(5*5) + 5)/5)^5 = 32🙂

    36 = (5!/(5+5))*(sqrt(5/.5)
    37 = (((5+5)/5)^5)+5
    38 = (5!/(5*.5))-5-5
    39 = (5!/(5*.5)) -5/.5
    40 = ((5*5)/.5) -5-5
  4. Sigulda
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    13 Sep '09 16:25
    About LaTeX - Thread 119064
  5. Joined
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    13 Sep '09 18:36
    41 = 5*(5+5)-5/.5
  6. Standard memberPalynka
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    13 Sep '09 20:21
    LaTeX with greasemonkey for those using Firefox.
    Thread 108499
  7. Sigulda
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    13 Sep '09 20:39
    Originally posted by Palynka
    LaTeX with greasemonkey for those using Firefox.
    Thread 108499
    Thanks for that.

    Now back to the topic

    42 = meaning of li.... = ...
  8. Standard memberAgerg
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    13 Sep '09 23:29
    42 = ((5*5)/.5) - sqrt(5/.5)
  9. Joined
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    14 Sep '09 20:574 edits
    43 = 5!/sqrt(5/.5) + sqrt(5/.5)
    44 = 5*5/.5 - 5/5
    45 = 5*5/.5 - 5 + 5
    46 = 5*5/.5 + 5/5
    47 = (5*5 + .5 + .5)/.5
    48 = 5!/5*(5+5)/5
    49 = 5*(5+5)-5/5
    50 = 5*(5+5)-5+5
    51 = 5*(5+5)+5/5
  10. Standard memberAgerg
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    15 Sep '09 05:316 edits
    52 = (5*5 +(5/5))/.5
    53 = 55 - (5+5)/5
    54 = 55 -5^(5-5)
    55 = 55 -5*(5-5)
    56 = 55 +5^(5-5)
    57 = 55+ (5+5)/5
    58 = 5!/(5*.5) +5+5
    59 = 55 + 5 - (5/5)
    60 = 55 + 5*(5/5)
    61 = 55 +5 + (5/5)
  11. Standard memberTheMaster37
    Kupikupopo!
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    15 Sep '09 09:16
    I think I'll skip.

    .5 is 0.5, so it uses a zero we don't get.

    sqrt uses a 2

    Factorial is a function, not an operation.

    0.555.... uses at least three 5's as typed here. Creating an abbreviation feels like cheating.
  12. Joined
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    19 Sep '09 00:08
    62:

    5.5 x 5.5 x ( 5/5 + 5/5) + 0.5 + 0.5 + 0.5

    thats probably too many fives
  13. Fichtekränzi
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    20 Sep '09 20:11
    With too many 5s, its easy:
    62 = 55 + 5 + 5/5 + 5/5
    ...still thinking...
  14. Joined
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    20 Sep '09 21:514 edits
    62 = 5*5*5*.5 - .5
    63 = 5*5*5*.5 + .5
    64 = (5! + (5 - .5)/.5)*.5
    65 = (5! + (5 + .5)/.5)*.5
  15. Standard memberPBE6
    Bananarama
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    21 Sep '09 20:101 edit
    Oops!
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