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Posers and Puzzles

converging to it

Joined 21 Aug '06 Moves 11458 I know four fours have been done here (not sure about 5 5s though)
You have to form the numbers from 0-whatever (in ascending order) using simple arithmetic operations. These being:
addition +
subtraction -
multiplication *
division /
factorial !
concatenation (eg: 55 or.55 etc...)
decimals . (ie .5)
recurring decimals (no overbar (or underline) so will let .5 denote .555555.... = 5/9)
square roots sqrt() (debatable because of implied 1/2 but then factorial has implied 2,3,4 in it yet no-one says anything about that)
exponentiation ^
Also since the first 30 or so are trivial should we start a bit later?

Sigulda

Joined 09 Sep '09 Moves 345 5!/5 + 5 + 5/5 = 30
5*5 + 5 + 5/5 = 31
Hmmm...... = 32
5.5 * 5 + 5.5 = 33
5!/5 + sqrt(5)*sqrt(5) + 5 = 34
5(5 + 5/5) + 5 = 35
LaTeX would make this forum much nicer, though it's not that easy to implement probably.

converging to it

Joined 21 Aug '06 Moves 11458 Originally posted by Kristaps
5!/5 + 5 + 5/5 = 30
5*5 + 5 + 5/5 = 31
Hmmm...... = 32
5.5 * 5 + 5.5 = 33
5!/5 + sqrt(5)*sqrt(5) + 5 = 34
5(5 + 5/5) + 5 = 35
LaTeX would make this forum much nicer, though it's not that easy to implement probably. Yeah I agree with you about the LaTeX...the boldface for recuring .5... looks crappy!

((sqrt(5*5) + 5)/5)^5 = 32đź™‚

36 = (5!/(5+5))*(sqrt(5/

.5 )

37 = (((5+5)/5)^5)+5

38 = (5!/(5*.5))-5-5

39 = (5!/(5*.5)) -5/

.5
40 = ((5*5)/.5) -5-5

Sigulda

Joined 09 Sep '09 Moves 345 About LaTeX -

Thread 119064

Joined 26 Apr '03 Moves 25818

Halfway

Joined 02 Aug '04 Moves 8702 LaTeX with greasemonkey for those using Firefox.

Thread 108499

Sigulda

Joined 09 Sep '09 Moves 345 Originally posted by Palynka
LaTeX with greasemonkey for those using Firefox.
Thread 108499 Thanks for that.

Now back to the topic

42 = meaning of li.... = ...

converging to it

Joined 21 Aug '06 Moves 11458 42 = ((5*5)/.5 ) - sqrt(5/.5 )

Joined 26 Apr '03 Moves 25818 43 = 5!/sqrt(5/.5 ) + sqrt(5/.5 )
44 = 5*5/.5 - 5/5
45 = 5*5/.5 - 5 + 5
46 = 5*5/.5 + 5/5
47 = (5*5 + .5 + .5 )/.5
48 = 5!/5*(5+5)/5
49 = 5*(5+5)-5/5
50 = 5*(5+5)-5+5
51 = 5*(5+5)+5/5

converging to it

Joined 21 Aug '06 Moves 11458 52 = (5*5 +(5/5))/.5
53 = 55 - (5+5)/5
54 = 55 -5^(5-5)
55 = 55 -5*(5-5)
56 = 55 +5^(5-5)
57 = 55+ (5+5)/5
58 = 5!/(5*.5) +5+5
59 = 55 + 5 - (5/5)
60 = 55 + 5*(5/5)
61 = 55 +5 + (5/5)

Out of my mind

Joined 25 Oct '02 Moves 20443 I think I'll skip.
.5 is 0.5, so it uses a zero we don't get.
sqrt uses a 2
Factorial is a function, not an operation.
0.555.... uses at least three 5's as typed here. Creating an abbreviation feels like cheating.

Joined 18 Mar '08 Moves 840 62:
5.5 x 5.5 x ( 5/5 + 5/5) + 0.5 + 0.5 + 0.5
thats probably too many fives

FichtekrĂ¤nzi

Joined 28 Mar '07 Moves 20109 With too many 5s, its easy:
62 = 55 + 5 + 5/5 + 5/5
...still thinking...

Joined 26 Apr '03 Moves 25818 62 = 5*5*5*.5 - .5
63 = 5*5*5*.5 + .5
64 = (5! + (5 - .5 )/.5 )*.5
65 = (5! + (5 + .5 )/.5 )*.5

False berry

Joined 14 Feb '04 Moves 28719