I know four fours have been done here (not sure about 5 5s though)
You have to form the numbers from 0-whatever (in ascending order) using simple arithmetic operations. These being:
addition +
subtraction -
multiplication *
division /
factorial !
concatenation (eg: 55 or.55 etc...)
decimals . (ie .5)
recurring decimals (no overbar (or underline) so will let .5 denote .555555.... = 5/9)
square roots sqrt() (debatable because of implied 1/2 but then factorial has implied 2,3,4 in it yet no-one says anything about that)
exponentiation ^
Also since the first 30 or so are trivial should we start a bit later?
Originally posted by KristapsYeah I agree with you about the LaTeX...the boldface for recuring .5... looks crappy!
5!/5 + 5 + 5/5 = 30
5*5 + 5 + 5/5 = 31
Hmmm...... = 32
5.5 * 5 + 5.5 = 33
5!/5 + sqrt(5)*sqrt(5) + 5 = 34
5(5 + 5/5) + 5 = 35
LaTeX would make this forum much nicer, though it's not that easy to implement probably.
((sqrt(5*5) + 5)/5)^5 = 32🙂
36 = (5!/(5+5))*(sqrt(5/.5)
37 = (((5+5)/5)^5)+5
38 = (5!/(5*.5))-5-5
39 = (5!/(5*.5)) -5/.5
40 = ((5*5)/.5) -5-5
Originally posted by PalynkaThanks for that.
LaTeX with greasemonkey for those using Firefox.
Thread 108499
Now back to the topic
42 = meaning of li.... = ...