- 12 Nov '03 15:57If there are 100 people from Hollywood at a party and each shakes the hand of every other person, how many handshakes take place?

1.) Total Handshakes = ________________________________________

Show all work here:

2.) What meathod did you use to solve this problem? You must use complete sentences.

Thanx. And You can thank me Lord Burn

-I am the master of Golden Sun no one can beat me not The Fusion Dragon not Deadbeard nobody. HA HA HA ! - 12 Nov '03 21:45 / 2 editsIf there are 100 people from Hollywood at a party and each shakes the hand of every other person, how many handshakes take place?

1.) Total Handshakes = 100 x 100 - 100 = 9900 handshakes

Show all work here:

2.) What meathod did you use to solve this problem?

Just guessing: 100 people times 100 people minus themselves (because they won't shake their own hands). That's, of course, assuming that all the people in the room have all their limbs. ~~skeeter~~515 + 30 days12 Nov '03 22:55 / 1 edit

Wrong - assuming that every-one has two hands then it is 400 x 400 (left to right/left to left/right to right/right to left] minus 300{we are only able to shake withourselves just once) which equals 159,700 in total*Originally posted by phisherman***If there are 100 people from Hollywood at a party and each shakes the hand of every other person, how many handshakes take place?**

1.) Total Handshakes = 100 x 100 - 100 = 9900 handshakes

Show all work here:

2.) What meathod d ...[text shortened]... se, assuming that all the people in the room have all their limbs.

skeeter- 12 Nov '03 23:20 / 1 edit

Person 1 shakes the hand of 99 others. Person 2 shakes the hand of 98 others, as he has already shaken the hand of person 1. Continuing with this pattern, the answer is the 99th triangular number.

Formula for triangular numbers = (1/2 x)(x-1)

Substitute 99 into the formula

49.5 * 98

which equals 4851. So 4851 handshakes take place. ~~skeeter~~515 + 30 days13 Nov '03 08:15

Er, everyone is ignoring the fact that we can shake hands with another person in one of four ways - to wit :*Originally posted by royalchicken***Er, 100 people each shake hands with 99 people, with two people per handshake. That's 9900/2 = 4950.**

KFC Bognor is basically right, except he used the wrong TN. It should be 99+98+97+96+95+...+1 = (99^2 + 99)/2 = 4950.

1. Right to (their) right

2. Right to (their) left

3. Left to (their) left

4. Left to (their) right

and we can also shake hands with-ourselves. Once!

skeeter firmly esconced in the 159,700 camp.- 13 Nov '03 18:11
If there are 100 people from Hollywood at a party and each shakes the hand of every other person, how many handshakes take place?

More to the point, how many new film get made?

I agree with RC the obvious answer is 4,950. But if each person shakes the hand of every other person, and assuming that every other person has two hands, the answer must be doubled. That is every person at the party shakes the left hand and the right hand of every other person = 9,900. It is irrelevant the number of combinations of shaking a right or a left hand because you only have to shake each hand once. The question also clearly states "the hand of every OTHER person", so no need to include your left hand shaking your right hand in the calculation. - 13 Nov '03 20:08

Of source "Every other person" might mean that each person only shakes with half of the other people....*Originally posted by kingofthe303***More to the point, how many new film get made?**

I agree with RC the obvious answer is 4,950. But if each person shakes the hand of every other person, and assuming that every other person has two hands, the answer must be doubled. That is every person at the party shakes the left hand and the right hand of every other person = 9,900. It is irreleva ...[text shortened]... HER person", so no need to include your left hand shaking your right hand in the calculation. - 16 Nov '03 20:13jeulious cezar, although a bit antisocial, and epileptic, was very good at parties, he would only show up for like an hour, but he would make a point of talking to _everyone_ there during that time, this is one of the reasons that he was so popular.

is the 99th triangle number the same as (99!)? - 16 Nov '03 21:45 / 1 edit

No, the 99th triangular number is the number of ways of selecting 2 items out of 100 things, with order of no consequence, or 99*100/2 = 4950.*Originally posted by fearlessleader***jeulious cezar, although a bit antisocial, and epileptic, was very good at parties, he would only show up for like an hour, but he would make a point of talking to _everyone_ there during that time, this is one of the reasons that he was so popular.**

is the 99th triangle number the same as (99!)?

99! = 99*98*97*96*95....*2 is very much larger. - 19 Nov '03 13:02Hi! Times up on this fourm thanx to your help i was able to get the correct answer

If there are 100 people from Hollywood at a party and each shakes the hand of every other person, how many handshakes take place?

1.) Total Handshakes = 4950

Show all work here:

100 people each shake hands with 99 people, with two people per handshake. That's 9900/2 = 4950.

It should be 99+98+97+96+95+...+1 = (99^2 + 99)/2 = 4950.

2.) What method did you use to solve this problem? You must use complete sentences.

The method I used to solve this problem is that when I first approached this problem I tried to come up with an algebraic equation such as solving for x. Then I got the equation 99+98+97+96+95+...+1 = x where x would = 4950. Then I simplified my equation to (99^2 + 99)/2 = x. This is how I approached this problem, using a method where I was trying to solve for x.

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I am the Master of Golden Sun no one can beat me not Tempest Lizard, not Satrous and Mernardi, not Dullahun, not Star Magician, not Doom Dragon, and ecpcally not you! HA HA HA! - 19 Nov '03 17:35
I am the Master of Golden Sun no one can beat me not Tempest Lizard, not Satrous and Mernardi, not Dullahun, not Star Magician, not Doom Dragon, and ecpcally not you! HA HA HA! [/b]

Hey, you have some sintax error. you message should be:

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I am the Master of Golden Sun<b>,<b> no one can beat me<b>,<b> not Tempest Lizard, not Satrous and Mernardi, not Dullahun, not Star Magician, not Doom Dragon, and ecpcally not you! HA HA HA! [/b]