29 Jul 06
Originally posted by Knight SquareFirst hose has a rate of 5/12 litres per second and the other hose has a rate of 5/25 litres per second.
Two hoses have a rate of 12s per 5L and 25s per 5L how long will it take to fill up a 150m^3 pool?
So the combined rate is 5/12+5/25 litres per second.
There 150*1000 litres to fill, so the total time needed is
150*1000/(5/12+5/25) = 9000000/37 seconds.
29 Jul 06
Originally posted by deriver69You have to keep them still so they keep Peeing in the pool. Also you have to keep them from pooping in the pool which would throw off the liquid calculation🙂
If like me you read horses instead of hoses it makes the idea of them filling a pool far more entertaining.
29 Jul 06
1 edit
Originally posted by SPMarsIf you divide out each contibutor, you get 5/12 of a liter per second or 0.41666 L/sec. The other one comes out at 5/25 or 0.2 L/sec. That makes 0.61666 L/sec filling the pool. Inverting that gives 1.6216 seconds per liter, times 1000 gives 1621.6 seconds to fill one cubic meter. Times 150 gives 243,245 seconds to fill the 150 M^3 pool.
First hose has a rate of 5/12 litres per second and the other hose has a rate of 5/25 litres per second.
So the combined rate is 5/12+5/25 litres per second.
There 150*1000 litres to fill, so the total time needed is
150*1000/(5/12+5/25) = 9000000/37 seconds.
The same as SP, but made the final division.
That problem can be restated as the current flowing in parallel in two resistors where they are charging a battery to X amount of joules of energy. It could be stated as 5/12 amp in one and 5/25 amp in the other. Same kind of problem.
30 Jul 06
Originally posted by ThudanBlunderin abc minutes tap A fills bc baths, B ac baths and C ab baths.
If
tap A fills a pool in a minutes
tap B fills a pool in b minutes
tap C fills a pool in c minutes
how long will they need to fill the pool when used together?
so a total of ab + bc + ac baths are filled in abc minutes.
so one bath is filled in abc/(ab + bc + ac)
30 Jul 06
Originally posted by sonhouseWhy would you do that? The words surrounding the numbers in these types of problems don't make a lick of difference.
That problem can be restated as the current flowing in parallel in two resistors where they are charging a battery to X amount of joules of energy. It could be stated as 5/12 amp in one and 5/25 amp in the other. Same kind of problem.
