Originally posted by THUDandBLUNDERI think it isn't possible.
[fen]rnbqkbnr/ppppppp1/8/8/8/6P1/PPPPPPP1/RNBQKBNR[/fen]
White has still all pieces, so all black pawns must have been on there own row.
Black has lost one pawn, which is explaining the dubble pawn of white, but the dubble pawn is on the g, and not on the h! But black is missing his h-pawn.
Are you really sure this is possible?
Originally posted by Mephisto2OK, but it is possible in 21 plies. 😛
How about this (not all moves are forced):
1.Na3 h5 2.Nb1 h4 3.Na3 h3 4.Nb1 Rh6 5.Na3 Rg6 6.Nb1 Rg3 7.hxg3 h2 8.Nf3 Nh6 9.Rg1 h1=R 10.Na3 Ng8 11.Nb1 Rh8 12.Rh1 Rh7 13.Ng1 Rh8
(Before BigDogg logs on, I realize I should have asked 'how could' rather than 'how did'.) 🙂
Originally posted by THUDandBLUNDER1.Nf3 h5 2.Rg1 Rh6 3.Rh1 Rg6 4.Rg1 Rg3 5.hxg3 h4 6.Nc3 h3 7.Nb1 h2 8.Nc3 h1=R 9.Nb1 Rh3 10.Rh1 Rh8 11.Ng1 is the fastest.
OK, but it is possible in 21 plies. 😛
(Before BigDogg logs on, I realize I should have asked 'how could' rather than 'how did'.) 🙂
However, it would be more interesting if the move order was exact...