# i swear, i'm not having you do my homework.

Posers and Puzzles 04 Aug '04 21:27
1. 04 Aug '04 21:27
give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist.
2. opsoccergurl11
rockin soccer kid
04 Aug '04 21:32
when put in a fraction form, does it have to be defined?
if not, then they're both zero
3. Acolyte
05 Aug '04 00:24
give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist.
B = sqrt(2)*A
4. TheMaster37
Kupikupopo!
06 Aug '04 17:59
Originally posted by opsoccergurl11
when put in a fraction form, does it have to be defined?
if not, then they're both zero
A / B = B / 2A
5. 07 Aug '04 18:59
Originally posted by Acolyte
B = sqrt(2)*A
thanks, A=1 and B=2^(1/2)

the master's answer is just a restatment of the problem. with this ratio, one can make a varation of the golden fractal, exept by halving the rectangles insted of removing a square.
6. TheMaster37
Kupikupopo!
07 Aug '04 20:34
My answer was how you derive the solution, wich is even more important then the solution itself. And if you look closely i replied to soccergurl, who claimed both A and B to be zero.
7. opsoccergurl11
rockin soccer kid
08 Aug '04 01:42
im probably wrong, right? after i posted, i looked back and realized that i didnt understand what it was really asking
8. TheMaster37
Kupikupopo!
08 Aug '04 12:03
*nods*

My post is the problem restated into an equation, you can solve it to obtain what Acolyte posted ðŸ™‚

A/B = B/2A

2AA = BB

+/- sqrt(2)A = B

Acolyte didn't give the negative solution for some reason...