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i swear, i'm not having you do my homework.

i swear, i'm not having you do my homework.

Posers and Puzzles

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give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist.

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when put in a fraction form, does it have to be defined?
if not, then they're both zero

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Originally posted by fearlessleader
give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist.
B = sqrt(2)*A

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Originally posted by opsoccergurl11
when put in a fraction form, does it have to be defined?
if not, then they're both zero
A / B = B / 2A

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Originally posted by Acolyte
B = sqrt(2)*A
thanks, A=1 and B=2^(1/2)

the master's answer is just a restatment of the problem. with this ratio, one can make a varation of the golden fractal, exept by halving the rectangles insted of removing a square.

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My answer was how you derive the solution, wich is even more important then the solution itself. And if you look closely i replied to soccergurl, who claimed both A and B to be zero.

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im probably wrong, right? after i posted, i looked back and realized that i didnt understand what it was really asking

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*nods*

My post is the problem restated into an equation, you can solve it to obtain what Acolyte posted 🙂

A/B = B/2A

2AA = BB

+/- sqrt(2)A = B

Acolyte didn't give the negative solution for some reason...