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Posers and Puzzles

my head

Joined 03 Oct '03 Moves 671 give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist.

over there

Joined 09 Jun '04 Moves 3002 when put in a fraction form, does it have to be defined?
if not, then they're both zero

Loughborough

Joined 04 Jul '02 Moves 3790 Originally posted by fearlessleader
give two numbers A and B such that A:B::B:2A
or prove that no such pair can exist. B = sqrt(2)*A

Out of my mind

Joined 25 Oct '02 Moves 20443 Originally posted by opsoccergurl11
when put in a fraction form, does it have to be defined?
if not, then they're both zero A / B = B / 2A

my head

Joined 03 Oct '03 Moves 671 Originally posted by Acolyte
B = sqrt(2)*A thanks, A=1 and B=2^(1/2)

the master's answer is just a restatment of the problem. with this ratio, one can make a varation of the golden fractal, exept by halving the rectangles insted of removing a square.

Out of my mind

Joined 25 Oct '02 Moves 20443 My answer was how you derive the solution, wich is even more important then the solution itself. And if you look closely i replied to soccergurl, who claimed both A and B to be zero.

over there

Joined 09 Jun '04 Moves 3002 im probably wrong, right? after i posted, i looked back and realized that i didnt understand what it was really asking

Out of my mind

Joined 25 Oct '02 Moves 20443 *nods*
My post is the problem restated into an equation, you can solve it to obtain what Acolyte posted ðŸ™‚
A/B = B/2A
2AA = BB
+/- sqrt(2)A = B
Acolyte didn't give the negative solution for some reason...