03 Oct '16 10:32>
I get a mental block with the following type of problems you come across from time to time.
I'm not bothered about the answer but I would like to know how to form the necessary equations.
I get so far and then my mind goes into meltdown.
If someone could please give me the equations, I'll be able to see where I go wrong:-
5 people's ages a,b,c,d,e
a=a+b+c+d+e/5 -this is easy - 4a =b+c+d+e.
Now comes the awkward bits:-
when B= 3a , a+c = a+b+c+d+e
and d =3d (obviously 'cos if b is 3 times his age the other four must be as well)) and e =(2b +1)
All the 5 ages are <50
What are the five ages?
I'm not bothered about the answer but I would like to know how to form the necessary equations.
I get so far and then my mind goes into meltdown.
If someone could please give me the equations, I'll be able to see where I go wrong:-
5 people's ages a,b,c,d,e
a=a+b+c+d+e/5 -this is easy - 4a =b+c+d+e.
Now comes the awkward bits:-
when B= 3a , a+c = a+b+c+d+e
and d =3d (obviously 'cos if b is 3 times his age the other four must be as well)) and e =(2b +1)
All the 5 ages are <50
What are the five ages?