Posers and Puzzles

Posers and Puzzles

  1. Palmerston North
    Joined
    02 Jun '06
    Moves
    2420
    04 Jun '06 21:50
    This is a FORCES question,
    f1=5600N
    d1=100cm
    f2= ??X??
    d2=8000cm

    Work out ??X?? and while your at it work out Turning MOMENT!

    Hint: Moment = Force * Distance
    ie. M=FD
    Hint: Think of a see-saw with those numbers, numbers being f1,d1...
  2. Standard membersonhouse
    Fast and Curious
    slatington, pa, usa
    Joined
    28 Dec '04
    Moves
    52874
    05 Jun '06 00:08
    Originally posted by Knight Square
    This is a FORCES question,
    f1=5600N
    d1=100cm
    f2= ??X??
    d2=8000cm

    Work out ??X?? and while your at it work out Turning MOMENT!

    Hint: Moment = Force * Distance
    ie. M=FD
    Hint: Think of a see-saw with those numbers, numbers being f1,d1...
    Wouldn't be 80 X 5600 by any chance?
  3. Standard memberXanthosNZ
    Cancerous Bus Crash
    p^2.sin(phi)
    Joined
    06 Sep '04
    Moves
    25076
    05 Jun '06 00:42
    f2 = 7N
    Also the turning moment provided by f2 is 7*80 = 560Nm.
    (Note that you work in metres as helps prevent stupid errors).

    This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
  4. Standard memberroyalchicken
    CHAOS GHOST!!!
    Elsewhere
    Joined
    29 Nov '02
    Moves
    17317
    05 Jun '06 00:50
    Originally posted by XanthosNZ
    f2 = 7N
    Also the turning moment provided by f2 is 7*80 = 560Nm.
    (Note that you work in metres as helps prevent stupid errors).

    This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
    I was going to ask OP if xyr Teacher said it was in equilibrium and whether xyr teacher agreed.
  5. Palmerston North
    Joined
    02 Jun '06
    Moves
    2420
    05 Jun '06 05:47
    Originally posted by Knight Square
    This is a FORCES question,
    f1=5600N
    d1=100cm
    f2= ??X??
    d2=8000cm

    Work out ??X?? and while your at it work out Turning MOMENT!

    Hint: Moment = Force * Distance
    ie. M=FD
    Hint: Think of a see-saw with those numbers, numbers being f1,d1...
    I know the question was not written out well.

    The Answers:
    f2=70N
    MOMENT was equal in both direction
    Moment = f1 X d1
    or
    Moment = f2 X d2
    The answer being:
    560000Ncm = 5600 X 100,
    ' ' = 8000 X 70,

    The Answer should be:
    5600Nm, because someone said that the measurements should be in metres.

    Thanks
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