05 Jun 06
Originally posted by Knight SquareWouldn't be 80 X 5600 by any chance?
This is a FORCES question,
f1=5600N
d1=100cm
f2= ??X??
d2=8000cm
Work out ??X?? and while your at it work out Turning MOMENT!
Hint: Moment = Force * Distance
ie. M=FD
Hint: Think of a see-saw with those numbers, numbers being f1,d1...
05 Jun 06
f2 = 7N
Also the turning moment provided by f2 is 7*80 = 560Nm.
(Note that you work in metres as helps prevent stupid errors).
This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
05 Jun 06
Originally posted by XanthosNZI was going to ask OP if xyr Teacher said it was in equilibrium and whether xyr teacher agreed.
f2 = 7N
Also the turning moment provided by f2 is 7*80 = 560Nm.
(Note that you work in metres as helps prevent stupid errors).
This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
05 Jun 06
Originally posted by Knight SquareI know the question was not written out well.
This is a FORCES question,
f1=5600N
d1=100cm
f2= ??X??
d2=8000cm
Work out ??X?? and while your at it work out Turning MOMENT!
Hint: Moment = Force * Distance
ie. M=FD
Hint: Think of a see-saw with those numbers, numbers being f1,d1...
The Answers:
f2=70N
MOMENT was equal in both direction
Moment = f1 X d1
or
Moment = f2 X d2
The answer being:
560000Ncm = 5600 X 100,
' ' = 8000 X 70,
The Answer should be:
5600Nm, because someone said that the measurements should be in metres.
Thanks