 Listening to your Teacher when at school? Knight Square Posers and Puzzles 04 Jun '06 21:50
1. 04 Jun '06 21:50
This is a FORCES question,
f1=5600N
d1=100cm
f2= ??X??
d2=8000cm

Work out ??X?? and while your at it work out Turning MOMENT!

Hint: Moment = Force * Distance
ie. M=FD
Hint: Think of a see-saw with those numbers, numbers being f1,d1...
2. 05 Jun '06 00:08
Originally posted by Knight Square
This is a FORCES question,
f1=5600N
d1=100cm
f2= ??X??
d2=8000cm

Work out ??X?? and while your at it work out Turning MOMENT!

Hint: Moment = Force * Distance
ie. M=FD
Hint: Think of a see-saw with those numbers, numbers being f1,d1...
Wouldn't be 80 X 5600 by any chance?
3. 05 Jun '06 00:42
f2 = 7N
Also the turning moment provided by f2 is 7*80 = 560Nm.
(Note that you work in metres as helps prevent stupid errors).

This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
4. 05 Jun '06 00:50
Originally posted by XanthosNZ
f2 = 7N
Also the turning moment provided by f2 is 7*80 = 560Nm.
(Note that you work in metres as helps prevent stupid errors).

This is of course assuming the system is in equilibrium (both rotationally due to the two moments from f1 and f2, and linearly due to a reaction force at the pivot).
I was going to ask OP if xyr Teacher said it was in equilibrium and whether xyr teacher agreed.
5. 05 Jun '06 05:47
Originally posted by Knight Square
This is a FORCES question,
f1=5600N
d1=100cm
f2= ??X??
d2=8000cm

Work out ??X?? and while your at it work out Turning MOMENT!

Hint: Moment = Force * Distance
ie. M=FD
Hint: Think of a see-saw with those numbers, numbers being f1,d1...
I know the question was not written out well.