1. Account suspended
    Joined
    16 Aug '05
    Moves
    1307
    29 Jun '06 06:10
    say a women owns a shop and the first day she had 13 customers the second day she had 14 customers the third 95 and the forth 62 customers what is the next amount of customers to come in?

    message the answer to me if u think u have it and explain why

    so others can suffer as i did
  2. Account suspended
    Joined
    16 Aug '05
    Moves
    1307
    29 Jun '06 08:01
    whoever can solve this gets to play me and im only 1255 ; )
  3. Joined
    11 Nov '05
    Moves
    43938
    29 Jun '06 09:221 edit
    Originally posted by WeakSoss
    say a women owns a shop and the first day she had 13 customers the second day she had 14 customers the third 95 and the forth 62 customers what is the next amount of customers to come in?

    message the answer to me if u think u have it and explain why

    so others can suffer as i did
    I say she will have 38 customers.
    Any answer will do in this guessing contest.
  4. London
    Joined
    04 Jun '06
    Moves
    929
    29 Jun '06 12:20
    Originally posted by WeakSoss
    say a women owns a shop and the first day she had 13 customers the second day she had 14 customers the third 95 and the forth 62 customers what is the next amount of customers to come in?

    message the answer to me if u think u have it and explain why

    so others can suffer as i did
    Would this by any chance be a shop selling pies?
  5. Standard memberuzless
    The So Fist
    Voice of Reason
    Joined
    28 Mar '06
    Moves
    9908
    29 Jun '06 16:00
    Originally posted by WeakSoss
    say a women owns a shop and the first day she had 13 customers the second day she had 14 customers the third 95 and the forth 62 customers what is the next amount of customers to come in?

    message the answer to me if u think u have it and explain why

    so others can suffer as i did
    zero, I'll explain why if i'm correct
  6. SubscriberBigDoggProblem
    The Advanced Mind
    bigdogghouse.com/RHP
    Joined
    26 Nov '04
    Moves
    117330
    29 Jun '06 16:21
    Originally posted by WeakSoss
    say a women owns a shop and the first day she had 13 customers the second day she had 14 customers the third 95 and the forth 62 customers what is the next amount of customers to come in?

    message the answer to me if u think u have it and explain why

    so others can suffer as i did
    You can't discount the possibility that the number of customers each day is completely random.

    Therefore, the puzzle has no clear solution.
  7. London
    Joined
    04 Jun '06
    Moves
    929
    29 Jun '06 16:44
    The puzzle has a definite answer and a clue to it is in my previous post. Prepare to feel stupid.
  8. Joined
    11 Nov '05
    Moves
    43938
    29 Jun '06 16:45
    Originally posted by BigDoggProblem
    Therefore, the puzzle has no clear solution.
    Exactly what I said earlier...
  9. London
    Joined
    04 Jun '06
    Moves
    929
    29 Jun '06 17:48
    Oh dear. You two are going around in circles.
  10. SubscriberBigDoggProblem
    The Advanced Mind
    bigdogghouse.com/RHP
    Joined
    26 Nov '04
    Moves
    117330
    29 Jun '06 19:101 edit
    Originally posted by TommyC
    The puzzle has a definite answer and a clue to it is in my previous post. Prepare to feel stupid.
    The problem is poorly set up because it does nothing to discount a purely random number of customers on any given day.

    Edit: I don't even know why I bothered posting this; you didn't understand it the first time, either.
  11. Standard memberuzless
    The So Fist
    Voice of Reason
    Joined
    28 Mar '06
    Moves
    9908
    29 Jun '06 19:49
    zero...the next day is sunday
  12. SubscriberBigDoggProblem
    The Advanced Mind
    bigdogghouse.com/RHP
    Joined
    26 Nov '04
    Moves
    117330
    29 Jun '06 19:521 edit
    Originally posted by uzless
    zero...the next day is sunday
    That's a better answer than the intended solution. The probability of the next day being sunday is higher than the probability of the intended solution.
  13. London
    Joined
    04 Jun '06
    Moves
    929
    29 Jun '06 20:11
    Originally posted by BigDoggProblem
    I don't even know why I bothered posting this; you didn't understand it the first time, either.
    Are you going to take that back, after I PM'd you the answer and explanation, along with the point of my first post on this thread, btw?!
  14. Joined
    11 Nov '05
    Moves
    43938
    29 Jun '06 20:261 edit
    Originally posted by TommyC
    Are you going to take that back, after I PM'd you the answer and explanation, along with the point of my first post on this thread, btw?!
    I totally agree to everyone that says that there is no unambiguous solution to this 'problem'. One answer is equally good as any other.

    If you want to convince me otherwise, you have to PM me as well.

    Edit: And a PM I got with an explanation.
  15. SubscriberAThousandYoung
    All My Soldiers...
    tinyurl.com/y9ls7wbl
    Joined
    23 Aug '04
    Moves
    24791
    29 Jun '06 20:391 edit
    35
Back to Top