1 edit
Originally posted by CrowleySounds like you need a few equations:
Hi guys, I need to do a calculation, but I can't find anything on the web to help me out.
Check this: http://www.redhotpawn.com/board/showthread.php?threadid=30250
1. Conservation of momentum:
m1*v1 + m2*v2 = m1*u1 + m2*u2
Where: m1, m2 are the masses of the objects; v1, v2 are the velocities before the collision; and u1, u2 are the velocities after the collision; and
2. Momentum/energy relation for an elastic collision:
0.5*m*(v^2) = dp/dt
Where: m is the mass of the object, v is the velocity, and dp/dt is the change in momentum over time.
What is the question exactly?
1 edit
Originally posted by CrowleyOK. It was accident.
Hi guys, I need to do a calculation, but I can't find anything on the web to help me out.
Check this: http://www.redhotpawn.com/board/showthread.php?threadid=30250
A motorbike hit a pedestrian, I want to know how fast the bastard was going.
I have the weight of the pedestrian and the bike and I have the displacement of the pedestrian.
What formula can I use?
http://www.redhotpawn.com/board/showthread.php?threadid=30250
The kinds of collision problems that are dealt with in low level physics are perfectly inelastic and elastic collisions. Your example is neither; it's an inelastic collision, but not perfectly inelastic. You need to know that kinetic energy is not conserved. However unlike a perfectly inelastic collision, the two bodies do not stick together and act like one body.
What you do know is that momentum is conserved. So, if you determine what the momentum of the pedestrian was, and you know the mass of the motorcycle and the rider including gas in the tank, you can figure out the velocity of the motorcycle. How would you do that though?
If you can determine the distance the person skidded on the concrete and the coefficient of friction between person and concrete, I think you can determine how fast the person was going when they hit.
It's a pretty complex problem and more information is needed to solve it.
