Sort This Out

Change this:


To This:



By removing three types of wetland.

(yes I'm bored.)

Originally posted by greenpawn34
Change this:

...By removing three types of wetland.

(yes I'm bored.)

Shouldnt that be by removing a type of wetland three times?

Hi Wolfgang.

You can put it anyway you want.

Or you can take away three half fences. It's up to you.

Originally posted by greenpawn34
Change this:

[fen][fen][fen][fen]rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR w KQkq - 0 1[/fen]
To This:

[fen]rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR w KQkq - 0 1[/fen]

By removing three types of wetland.

(yes I'm bored.)

No. Make me!!!

Originally posted by greenpawn34
Hi Wolfgang.

You can put it anyway you want.

Or you can take away three half fences. It's up to you.

Or the centre of your defence ...

Sorry, I don't follow.

Originally posted by greenpawn34
Change this:

[fen][fen][fen][fen]rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR w KQkq - 0 1[/fen]
To This:

[fen]rnbqkbnr/pppppppp/8/8/8/8/PPPPPPPP/RNBQKBNR w KQkq - 0 1[/fen]

By removing three types of wetland.

(yes I'm bored.)

Forgot about this - I'll give the solution.

If you look at the Reply & Quote you will see the first diagram was created with:

[fen][fen][fen][fen]

Putting[fen][fen][fen][fen] infront of the starting position gives you.



So if you remove 3 fens. (fen as in wet land and deFENce etc.) you get



As I said. I was bored.

why does [fen][fen][fen] do that?????

I have no idea.

It may be something to do with the White King and Black Knight.

putting [fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen][fen] infront on the initial position.




Gives you this.



after that is does not seem to matter how many 'fens' you place infront you always get this.
(anymore 'fens' (34) than those in the last diagram and it usually fails.)



16 Knights have checkmated 48 Kings.

Edit:
So there is a puzzle. (I knew some good would come of this).
Fill the board with White Kings.



Place as few Black Knights on the board as possbile so that every King is mated. (attacked).
The knack must be choosing which Kings to repalce with a Black Knight.

I get 12 like this:



Can it be done with less than 12?

I suppose an easier way to do it is get every square attackd
by as few Knights as possible. Then the answer is 12.

It has been sorted out.

what is the least number of Knights needed to checkmate a King in the middle of the board?

Edit: can it be done with less than 5? I'm guessing no given each Knight can only cover 2 squares adjacent to the King, even if they occupy another square.

Originally posted by andrew93
I get 12 like this:

[fen] KKKKKKKK/KKnKKKKK/KKnnKnnK/KKKKKnKK/KKnKKKKK/KnnKnnKK/KKKKKnKK/KKKKKKKK[/fen]

Can it be done with less than 12?

I don't think that is an answer


Some kings are not mated there, because they can take knights.

That would depend on an interpretation of the question - I was relying on the qualifier "attacked".

To get a solution where each and every King is check-mated (and not just attacked) I figure you need 4 more Knights.

Can it be done with less?

Andrew