system max

given:
y<-3(X-4)+5
y>0
and
A=X^2+Y^2
find the largest possible value of A.

Originally posted by fearlessleader
given:
y<-3(X-4)+5
y>0
and
A=X^2+Y^2
find the largest possible value of A.

289/10

Originally posted by fearlessleader
given:
y<-3(X-4)+5
y>0
and
A=X^2+Y^2
find the largest possible value of A.

i am not sure that this makes sense as written.
if y &lt; -3(x-4) +5, y will be positive for any x &lt; 17/3.
since x can be arbitrarily large negative and satisfy the conditions, A has no maximum.

Originally posted by BarefootChessPlayer
i am not sure that this makes sense as written.
if y < -3(x-4) +5, y will be positive for any x < 17/3.
since x can be arbitrarily large negative and satisfy the conditions, [b]A has no maximum.
[/b]

your right, typo.
should read y&lt;-3X^4=5

the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.

Originally posted by fearlessleader
your right, typo.
should read y<-3X^4=5

the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.

did you mean &quot;y&lt;= 3x^4=5&quot;?
the equation you gave has no real solutions. if you accept the above, the possible values for x are: (5/3)^0.25, its negative, and those times i.
if that's the case, any y less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for A again since now y can go large negative.
hope we can solve this one!

Originally posted by BarefootChessPlayer
did you mean "y<= 3x^4=5"?
the equation you gave has no real solutions. if you accept the above, the possible values for x are: (5/3)^0.25, its negative, and those times i.
if that's the case, any y less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for A again since now [b]y can go large negative.
hope we can solve this one![/b]

oops! i missed that y must be positive.
now maybe i can come up with a solution.
sorry!