11 Feb 04
Originally posted by fearlessleaderi am not sure that this makes sense as written.
given:
y<-3(X-4)+5
y>0
and
A=X^2+Y^2
find the largest possible value of A.
if y < -3(x-4) +5, y will be positive for any x < 17/3.
since x can be arbitrarily large negative and satisfy the conditions, A has no maximum.
12 Feb 04
Originally posted by BarefootChessPlayeryour right, typo.
i am not sure that this makes sense as written.
if y < -3(x-4) +5, y will be positive for any x < 17/3.
since x can be arbitrarily large negative and satisfy the conditions, [b]A has no maximum.
[/b]
should read y<-3X^4=5
the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.
12 Feb 04
2 edits
Originally posted by fearlessleaderdid you mean "y<= 3x^4=5"?
your right, typo.
should read y<-3X^4=5
the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.
the equation you gave has no real solutions. if you accept the above, the possible values for x are: (5/3)^0.25, its negative, and those times i.
if that's the case, any y less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for A again since now y can go large negative.
hope we can solve this one!
18 Feb 04
Originally posted by BarefootChessPlayeroops! i missed that y must be positive.
did you mean "y<= 3x^4=5"?
the equation you gave has no real solutions. if you accept the above, the possible values for x are: (5/3)^0.25, its negative, and those times i.
if that's the case, any y less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for A again since now [b]y can go large negative.
hope we can solve this one![/b]
now maybe i can come up with a solution.
sorry!