10 Feb '04 12:38

given:

y<-3(X-4)+5

y>0

and

A=X^2+Y^2

find the largest possible value of A.

y<-3(X-4)+5

y>0

and

A=X^2+Y^2

find the largest possible value of A.

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central usa11 Feb '04 03:42

i am not sure that this makes sense as written.*Originally posted by fearlessleader***given:**

y<-3(X-4)+5

y>0

and

A=X^2+Y^2

find the largest possible value of A.

if y < -3(x-4) +5,*y*will be positive for any*x*< 17/3.

since*x*can be arbitrarily large negative and satisfy the conditions,.*A*has*no*maximum- Joined
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my head12 Feb '04 16:24

your right, typo.*Originally posted by BarefootChessPlayer***i am not sure that this makes sense as written.**.

if y < -3(x-4) +5,*y*will be positive for any*x*< 17/3.

since*x*can be arbitrarily large negative and satisfy the conditions, [b]*A*has*no*maximum

[/b]

should read y<-3X^4=5

the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.- Joined
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central usa12 Feb '04 22:442 edits

did you mean "y<= 3x^4=5"?*Originally posted by fearlessleader***your right, typo.**

should read y<-3X^4=5

the point of this thread is that i to see if anyone knows how to find the maximum of nonlinear systems of inequalities.

the equation you gave has no real solutions. if you accept the above, the possible values for*x*are: (5/3)^0.25, its negative, and those times*i*.

if that's the case, any*y*less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for*A*again since nowcan go large negative.*y*

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central usa18 Feb '04 18:17

oops! i missed that*Originally posted by BarefootChessPlayer***did you mean "y<= 3x^4=5"?**can go large negative.

the equation you gave has no real solutions. if you accept the above, the possible values for*x*are: (5/3)^0.25, its negative, and those times*i*.

if that's the case, any*y*less than (5/3)^0.25 would be adequate, and thus you'd have no maximum for*A*again since now [b]*y*

hope we can solve this one![/b]*y*must be positive.

now maybe i can come up with a solution.

sorry!