*Originally posted by forkedknight*

**so extending this to 3 friends:
**

-one who is 6 miles out of the way

-one who is 10 miles out of the way

- and one who is 14 miles out of the way

and the total distance out of your way is 14 miles, how do you split it up?

I would take the same argument, leaving you with my previous answer to the original problem...

Excellent point, which means I would either have to revisit one of my two answers.

So let me attempt, then, to relook at your problem in the exact same manner, if indeed I can.

I will therefore suppose only two friends, one who lives 1 mile out (2 miles round trip), another 1.5 miles out (3 miles round trip), and 1.5 miles apart (so that it's 4 miles to take both home).

So now, let me examine how it would be divided depending on who gets taken home first.

Suppose the nearer goes home first..

That's 1 mile split, 1.5 miles for the further, and 1.5 miles to account for for my trip back home. When everyone was in a straight line of sorts, this was easier, as each was the reverse of a mile going, not the case this time around. I will answer this with the notion that I ought to divide it proportion to the miles for the trip there, assuming each was the only one.

So 0.5 + 0.0 + 0.6 miles for the nearer, and 0.5 + 1.5 + 0.9 for the further, or a $2.90/$1.10 split, further and nearer.

Now what if I take the further home first?

That would be 1.5 split, 1.5 to the nearer, and 1 divided as before.

Nearer is .75 + 1.5 + .4 = $2.65, and the further $1.35.

This analysis would seem patently unfair, as shown by its inconsistency.

I will have to revisit this when I have more time.