1. Joined
    15 Feb '07
    Moves
    667
    16 Jun '08 04:063 edits
    Aaah, I did so the summations for the available places...


    Starting with the center column, recalling that phi^2 = phi + 1, which means phi^2 - 1 = phi.

    1 + 1/phi + 1/phi^2 + 1/phi^3 + ...

    = sum(i=0 to inf, 1 / phi^i)
    = phi / (phi - 1)
    = (phi + 1 - 1) / (phi - 1)
    = (phi^2 - 1) / (phi - 1)
    = (phi + 1) * (phi - 1) / (phi - 1)
    = phi + 1
    = phi^2

    sum(i=0 to inf, 1 / phi^i) = phi^2

    The other columns have the same progression, but divide the total by phi once for every column to the side (and there are 2 sides)

    So the sum value of the entire thing is phi^2 (center) + 2 * phi + 2 + 2 / phi + ...

    = 2 * phi^2 * sum(i=0 to inf, 1 / phi^i) - phi^2
    = 2 * phi^2 * phi^2 - phi^2
    = phi^2 * (2 * phi^2 - 1)
    = phi^2 * (phi^2 + phi^2 - 1)
    = phi^2 * (phi^2 + phi)
    = phi^3 * (phi + 1)
    = phi^3 * phi^2
    = phi^5
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