Originally posted by GastelHow was that supposed to help? It directed me to a weight loss calculator.
I don't think he could possibly know what is the wieght of a fish.
Maybe this could help
http://www.softpile.com/Education/Science/Review_60001_index.html
I was just stating that if you look at his original question it is unclear.
If he was looking for 20 pounds, then the question should be stated as follows: What is the weight of a fish if half its wieght plus 10 pounds
equals its wieght?
Originally posted by zzywThe one I meant for 7 is provided by Fat Lady. It's the easiest (and only one) I know.
The algorithms for testing divisibility by 7 I've come across are all horribly complicated, do you know one that's relatively simple? From the top of my head, these are the divisibility tests I know up to 25:
1: trivial
2: even number
3: sum of digits is divisible by 3
4: last two digits divisible by 4
5: ends in 0 or 5
6: divisible by 2 and 3
7: ???
...[text shortened]... 8
25: ends in 00, 25, 50 or 75.
Does anyone know a clever way to fill some of the blanks?
Originally posted by joe shmoThat's not the question and it doesn't point you to a weight calculator.
How was that supposed to help? It directed me to a weight loss calculator.
I was just stating that if you look at his original question it is unclear.
If he was looking for 20 pounds, then the question should be stated as follows: What is the weight of a fish if half its wieght plus 10 pounds
equals its wieght?
Originally posted by joe shmosorry i guess the original question was wrong what JS has is correct and i am looking for the weight of the fish which is 20 pounds.
How was that supposed to help? It directed me to a weight loss calculator.
I was just stating that if you look at his original question it is unclear.
If he was looking for 20 pounds, then the question should be stated as follows: What is the weight of a fish if half its wieght plus 10 pounds
equals its wieght?
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Originally posted by tournymangrI take it your in algebra? Here is a question, Suzy has a garden with the dimensions of 5ft.X 9ft. She has two kinds of flowers and she has enough of one type of flower to make a uniform border inside her garden that has an area of 24 ft^2. The rest she will plant in the middle. What is the width of the uniform border of flowers?
sorry i guess the original question was wrong what JS has is correct and i am looking for the weight of the fish which is 20 pounds.
Originally posted by joe shmowell there are two ways i find to be the best route
I take it your in algebra? Here is a question, Suzy has a garden with the dimensions of 5ft.X 9ft. She has two kinds of flowers and she has enough of one type of flower to make a uniform border inside her garden that has an area of 24 ft^2. The rest she will plant in the middle. What is the width of the uniform border of flowers?
1) the border is 4x6
2) the border is 8x3
the third could be 12x2 but it doesnt fit
Originally posted by joe shmomaybe i just misunderstood the question? i thought you wanted to make a border. the best way should be just an area question no? you know you take the best answer and work with it? maybe i did do it wrong. can you explain more??
I think you are confused? Perhaps, if you show me how you tried to solve it I can help?
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Originally posted by tournymangrYou have a 5x9 space. You need a border of constant thickness within this - so you'll end up with a 5x9 rectangle with a rectangle cut out of the middle. You need to find the thickness of this border.
maybe i just misunderstood the question? i thought you wanted to make a border. the best way should be just an area question no? you know you take the best answer and work with it? maybe i did do it wrong. can you explain more??
Is that clear?
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Originally posted by mtthwYes, listen to him........I was going to attempt that visual, so thanks
You have a 5x9 space. You need a border of constant thickness within this - so you'll end up with a 5x9 rectangle with a rectangle cut out of the middle. You need to find the thickness of this border.
Is that clear?
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Originally posted by tournymangrYour close, Those are the dimensions of the inside border, but not the dimensions themselves. Your doing well using logic, you almost have it solved without algebra! Why havn't you used algebra to solve?
ok so we have the entire space being 45ft^2 and if you subtract 24ft^2 you have 21ft^2 which leaves a 7ftx3ft border.
i dont know if this is what you meant but i cant concentrate right now i dont know why.