Will the airplane fly?

Originally posted by skeeter
The 'pressure thing' that I refer to is the only 'thing' that enables a plane to fly. That pressure is created by the differing rates of flow over the two surfaces. Air flow over the longer surface, the top, is faster so less pressure whilst the flow over the shorter is relatively slower therefore more pressure and that is what produces the lift. Nothing else does.

skeeter

Originally posted by XanthosNZ
Wrong.

Have a look at:
http://en.wikipedia.org/wiki/Lift_%28force%29
http://en.wikipedia.org/wiki/Wing
http://en.wikipedia.org/wiki/Angle_of_attack
and
http://en.wikipedia.org/wiki/Airfoil

You'll find the statement you made in the misconception section of the Lift page.

I agree, you're wrong, there is more lift created over the top of the wing than there is at underneath.

Originally posted by flyUnity
A plane is standing on a runway that can move (some sort of treadmill). The plane moves in one direction, while the conveyer moves at the same speed but in the opposite direction. Can the plane take off?"

(copied and pasted from another source)

Originally posted by CrazyLilTing
No. And ATY has answered correctly (see the 2nd post).
Other answers I've read on this thread (that no agree with ATY post) only puts in evidence your poor understanding -if any- of elementary physics laws, not to speak of fluid mechanics.

Originally posted by XanthosNZ
Planes create forward motion by pushing on the air (which is stationary) and the wheels freely rotate (they aren't driving, they could easily be replaced with skids [and are in some planes]).

So normally a plane takes off by pushing on the air to create forward motion until it reaches a certain speed at which it takes off due to created lift.

On a tr orward motion creates lift.

EDIT: Note that ATY has admitted that his first post was wrong.

Originally posted by CrazyLilTing
Hi Xanthos,

I've don't read all the posts.

But only common sense dictates that if an airplane is trying to take off while being on a conveyer that takes it at 0 velocity measured with respect to the atmosphere,- which is the case formulated in the original question (may be I have misunderstood it)- it will never take off.

Edit: as long as the conveyer keep the airplane at velociry 0.

Originally posted by XanthosNZ
How would the conveyor belt keep the plane at 0 velocity with respect to the atmosphere?

Originally posted by CrazyLilTing
Easy. Imagine no wind velocity, may be only a mild breeze.
In ideal conditions, the velocity of air being 0 measured to the conveyor.
As far as the relative velocity of the airplane remains 0, so does the airplane (velociry) to the atmosphere.
If that numbers aren't exact, may be the plane could take off... But I can't imagine me driving an airplane in such conitiions, when the tale off is finite (in mathematical and practical tems 🙂 )

Originally posted by XanthosNZ
You have actually made no sense at all.

PS. Reading threads before posting in them is advised.

Originally posted by CrazyLilTing
thanks. I'll tale ur advise into account.
But if u think my post is nonsense, pls revise ur elementary lnowledege of Physics 101
You are better at math, I think.

Originally posted by XanthosNZ
I need to learn Physics because I can't understand your broken English?

Originally posted by KingsBishop

Originally posted by CrazyLilTing
My "broken english" is by no way a trouble to make sense of my posts. At least for you. Go ahead, and make your point, if you have one 🙂

Originally posted by XanthosNZ
Wrong.

Have a look at:
http://en.wikipedia.org/wiki/Lift_%28force%29
http://en.wikipedia.org/wiki/Wing
http://en.wikipedia.org/wiki/Angle_of_attack
and
http://en.wikipedia.org/wiki/Airfoil

You'll find the statement you made in the misconception section of the Lift page.