Originally posted by twhitehead
I understand your explanation about how the fuel burns hotter and faster, but I am still missing the point as to how that helps. Surely the total amount of energy from the fuel is converted to heat however fast it burns, or is it a case of the heat being lost out the exhaust valves?
I am not saying you are wrong about anything, I just want to understand it better.
http://en.wikipedia.org/wiki/Diesel_engine#How_diesel_engines_work
According to the above article, the diesel engine works by compressing the fuel adiabatically to 15-20 times normal pressure, thereby increasing the temperature of the fuel to ignition temperature. Also, as the fuel droplets vaporize from their surface, the vapours ignite and the droplet burns from the outside in. Both of these processes are mass transport phenomena where the rate of change of the droplet volume |dV/dt| increases with time, much the same way that peeling successive equally thick layers of an onion decreases the volume of the onion faster the closer you get to the middle.
The total amount of energy released from this combustion reaction would be the same no matter what rate it took place at (provided the reactions were the same), making the energy released a state function. However the amount of work done vs. the amount of heat generated is path dependent. One example of this is given in the same article:
http://en.wikipedia.org/wiki/Diesel_engine#Cold_weather
During cold weather starts, the amount of heat absorbed by the cold engine block decreases the amount of work done on the piston. In a normal engine, having a quicker explosion of fuel allows more of the work generated to be directed at the piston, and less heat being dissipated as random motion in the fuel and surrounding engine.