How to calculate radiance emitted?

Originally posted by FabianFnas
There has been a sub-discussion in this thread about probability zero. On argument states that "events of probability zero may happen". If find this impossible.

An event that has probability zero cannot happen!

If p=0 can happen, than anything can happen.
The probability that the sun is gone and been gone from the time Earth was into being has zer ...[text shortened]... ror in our calculation.

Bottom line: An event that has probability zero cannot happen!

An event with probability zero can happen. Palynka will show it to you after he is done building up his little climax, but you can read back in the thread as well.

Originally posted by KazetNagorra
Admittedly it's not my field of expertise. They don't teach it much.

You must be joking. So how are you intended to make anything out of a quantum mechanics course? 😕 😕 😕

Originally posted by FabianFnas
There has been a sub-discussion in this thread about probability zero. On argument states that "events of probability zero may happen". If find this impossible.

An event that has probability zero cannot happen!

If p=0 can happen, than anything can happen.
The probability that the sun is gone and been gone from the time Earth was into being has zer ...[text shortened]... ror in our calculation.

Bottom line: An event that has probability zero cannot happen!

Nice way to totally miss the point.

Do you even know how to differentiate a necessary condition from a sufficient one?

Originally posted by adam warlock
You just be joking. So how are you intended to make anything out of a quantum mechanics course? 😕 😕 😕

I didn't say they didn't teach it at all. Just the basic stuff which is enough for use in quantum mechanics.

Originally posted by KazetNagorra
Admittedly it's not my field of expertise. They don't teach it much.

Really? That strikes me as odd, considering the probabilistic view of quantum mechanics that I (possibly wrongly) have. I always thought it was an important part of it. I agree you don't need to go too deep, but a solid background could be done with one or two serious courses, especially considering you already have more than the mathematical background required.

Originally posted by adam warlock
Do you even know how to differentiate a necessary condition from a sufficient one?

lulz

Originally posted by KazetNagorra
I didn't say they didn't teach it at all. Just the basic stuff which is enough for use in quantum mechanics.

How do you know what is enough for quantum mechanics?

You don't know how to calculate the probability of a continuous variable so it's pretty safe to say that you know nothing about QM.

Originally posted by Palynka
P(X=x) = 0 for all x in the set of all reals. Do you agree, Mr. "Physicist"?

Exactly.
And if you multiply your result with the number of reals from -inf to +inf you get the result exactly=1. It's called integration and Newton, Leibnitz and co knew that very well, they invented integration.

Does this mean that you can show me a person with a height of exactly 180 cm of height? Even that a 180 cm man does not exist, P(X=180) = 0?
(Now, this is a trick question, so there is a posssible follower...)

And I never 'shriek' about being stalked unless there is a reason to. I don't mind having a discussion without personal attacks of every kind. Let's not talk more about this but continue to talk about the matter at hand.

Originally posted by FabianFnas
Exactly.
And if you multiply your result with the number of reals from -inf to +inf you get the result exactly=1. It's called integration and Newton, Leibnitz and co knew that very well, they invented integration.

Does this mean that you can show me a person with a height of exactly 180 cm of height? Even that a 180 cm man does not exist, P(X=180) = ...[text shortened]... f every kind. Let's not talk more about this but continue to talk about the matter at hand.

Now, now, don't jump the gun. We have to go slowly or you'll never get it.

So.

Make 20 draws from that normal distribution. Label the numbers drawn as y1, y2, ... , y20. (You understand what I mean by "..." ,right?

Are you with me?

Originally posted by FabianFnas
Does this mean that you can show me a person with a height of exactly 180 cm of height? Even that a 180 cm man does not exist, P(X=180) = 0?
(Now, this is a trick question, so there is a posssible follower...)

You're hopeless! 😞

Originally posted by Palynka
Now, now, don't jump the gun. We have to go slowly or you'll never get it.

So.

Make 20 draws from that normal distribution. Label the numbers drawn as y1, y2, ... , y20. (You understand what I mean by "..." ,right?

Are you with me?

I'm starting to think you're a saint.

Originally posted by Palynka
Now, now, don't jump the gun. We have to go slowly or you'll never get it.

So.

Make 20 draws from that normal distribution. Label the numbers drawn as y1, y2, ... , y20. (You understand what I mean by "..." ,right?

Are you with me?

Go on, perhaps I know what you're talking about... Math, right? 😉

Originally posted by FabianFnas
Go on, perhaps I know what you're talking about... Math, right? 😉

Ok, so calculate the following probabilities:

P(X = y1)
P(X = y2)
...
P(X = y20)

Originally posted by adam warlock
You're hopeless! 😞

I am, right? Well, I'm not a giant.

Originally posted by adam warlock
How do you know what is enough for quantum mechanics?

You don't know how to calculate the probability of a continuous variable so it's pretty safe to say that you know nothing about QM.

I do know how to calculate the probability of a continuous variable. You take a probability density function and integrate.