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  1. Joined
    30 Sep '14
    Moves
    4618
    07 May '18 14:56
    Hi,

    In this tournament: http://tinyurl.com/ycpaezc8 why were the groups paired in an uneven fashion?

    The previous round had the groups more logically paired. But I cannot comprehend the logic for the third round. It almost seems like a random paring. Shouldn't it be groups of two?

    [gid]https://www.redhotpawn.com/tournament/view.php?tid=26891&rndid=3&issummaryview=[/gid]
  2. Subscribervenda
    Dave
    S.Yorks.England
    Joined
    18 Apr '10
    Moves
    61264
    09 May '18 13:25
    Originally posted by @acw
    Hi,

    In this tournament: http://tinyurl.com/ycpaezc8 why were the groups paired in an uneven fashion?

    The previous round had the groups more logically paired. But I cannot comprehend the logic for the third round. It almost seems like a random paring. Shouldn't it be groups of two?

    [gid]https://www.redhotpawn.com/tournament/view.php?tid=26891&rndid=3&issummaryview=[/gid]
    I've not looked at the actual tournament , but in every tournament I've ever considered it has stated pairing -random although usually it works out roughly in T.E.R order
  3. Joined
    30 Sep '14
    Moves
    4618
    11 May '18 22:391 edit
    Never mind. There are only five players in all.
  4. SubscriberKewpie
    since 1-Feb-07
    Joined
    20 Jan '09
    Moves
    325586
    14 May '18 04:37
    If there is a leftover player in a round (because of draws from earlier rounds) the first grouping will be a trio rather than a pair.
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