1+1=1

Given:

x=1
x=y

Then:

xy=x2

xy-y2=x2-y2

y(x-y)=(x+y)(x-y)
-------------------- =
(x-y)

y=x+y

1+1=1

Q.E.D.

Originally posted by abejnood
Given:

x=1
x=y

Then:

xy=x2

xy-y2=x2-y2

y(x-y)=(x+y)(x-y)
-------------------- =
(x-y)

y=x+y

1+1=1

Q.E.D.

Originally posted by Remora91
hows ur edoocayshun going down in tenesssey?

Originally posted by abejnood
Given:

x=1
x=y

Then:

xy=x2

xy-y2=x2-y2

y(x-y)=(x+y)(x-y)
-------------------- =
(x-y)

y=x+y

1+1=1

Q.E.D.

Dividing by zero is Naughty Maths.

It is also very boring 😞

Originally posted by ark13
Tricky, but logically incorrect. You divide both sides by (x-y), which is equal to zero. Dividing by zero is illegal mathematically.

Originally posted by Bowmann
Dividing by zero is Naughty Maths.

It is also very boring 😞

Originally posted by Bowmann
Dividing by zero is Naughty Maths.

It is also very boring 😞

Originally posted by ark13
I think I've discovered multiple account abuse.

0=0
0*anything=0
Therefore I can multiply the left side by Bowmann
Bowmann * 0=0
and the right side by abejnood
Bowmann * 0=abejnood * 0
Divide both sides by zero
Bowmann = abejnood
I've finally caught you

*alerting mods*

Originally posted by ark13
I think I've discovered multiple account abuse.

0=0
0*anything=0
Therefore I can multiply the left side by Bowmann
Bowmann * 0=0
and the right side by abejnood
Bowmann * 0=abejnood * 0
Divide both sides by zero
Bowmann = abejnood
I've finally caught you

*alerting mods*

Originally posted by Bowmann
No. You're seriously underestimating the value of Bowmann.

1 + 1 = window

Originally posted by Remora91
hows ur edoocayshun going down in tenesssey?

Originally posted by abejnood
Given:

x=1
x=y

Then:

xy=x2

xy-y2=x2-y2

y(x-y)=(x+y)(x-y)
-------------------- =
(x-y)

y=x+y

1+1=1

Q.E.D.

Originally posted by abejnood
Given:

x=1
x=y

Then:

xy=x2

xy-y2=x2-y2

y(x-y)=(x+y)(x-y)
-------------------- =
(x-y)

y=x+y

1+1=1

Q.E.D.