1. Joined
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    16 Apr '08 11:121 edit
    Originally posted by heinzkat
    Is there already 50 move rule danger? That would explain the problem perhaps. Then it'd be 1. Rxg6 (?) with Qf1#.
    Makes sense as an idea. Now who's going to do the 99% fieldwork, lol.

    edit. it doesn't explain the mate in 3 (and not 2) part, I think
  2. Standard memberjockmcgee
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    16 Apr '08 14:39
    Originally posted by Mephisto2
    Makes sense as an idea. Now who's going to do the 99% fieldwork, lol.

    edit. it doesn't explain the mate in 3 (and not 2) part, I think
    Does it not solve it if we have:
    1. Rxg6 Rg8+
    2. Rxg8 ...
    3. Qf1#
    ?
  3. Joined
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    16 Apr '08 14:42
    Originally posted by jockmcgee
    Does it not solve it if we have:
    1. Rxg6 Rg8+
    2. Rxg8 ...
    3. Qf1#
    ?
    Maybe, but Black can play 2. ... Kg1! For the rest, SwissGambit will probably insist we give the full retrogradic proof, instead this link will do;

    http://www.mrmip.net/mipsofacto/plaksin.htm
  4. Joined
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    16 Apr '08 14:44
    Originally posted by Mephisto2
    Makes sense as an idea. Now who's going to do the 99% fieldwork, lol.

    edit. it doesn't explain the mate in 3 (and not 2) part, I think
    Oh yes, because else after 1. Qf1+ Black can claim the draw. With 1. Rxg6 Black has nothing left.
  5. Standard memberjockmcgee
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    16 Apr '08 14:55
    Originally posted by heinzkat
    Maybe, but Black can play 2. ... Kg1! For the rest, SwissGambit will probably insist we give the full retrogradic proof, instead this link will do;

    http://www.mrmip.net/mipsofacto/plaksin.htm
    Retrogradic proofs being beyond me, I'll just correct myself on what I meant before 🙂

    If black plays 2. ... Kg1! doesn't 3. Qe1# work?
  6. Joined
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    16 Apr '08 15:33
    Originally posted by heinzkat
    Oh yes, because else after 1. Qf1+ Black can claim the draw. With 1. Rxg6 Black has nothing left.
    correct. Thanks for saving us the hard work with the link 😉
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    16 Apr '08 16:25


    White to move. Mate in a few moves [six at most]; should be possible to figure out.
  8. Standard memberSwissGambit
    Caninus Interruptus
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    16 Apr '08 17:053 edits
    Originally posted by heinzkat
    [fen]2r1kb1r/p2n1p2/8/3R1N1p/Pp1p4/5Q1P/1q4P1/5RK1 w - -[/fen]

    White to move. Mate in a few moves [six at most]; should be possible to figure out.
    Thank god I have my chess engine to spare me the hard work of actually solving this.

    1.Sf5-g7 + !
    1...Ke8-d8 2.Rd5*d7 + 2...Kd8*d7 3.Qf3-d5 + [quote] 3...Kd7-e7 4.Rf1*f7 #
    3...Kd7-c7 4.Rf1*f7 + [quote] 4...Kc7-b8 5.Qd5-b7 #
    4...Kc7-b6 5.Qd5-b5 #
    4...Bf8-e7 5.Rf7*e7 +[quote] 5...Kc7-b8 6.Qd5-b7 #
    5...Kc7-b6 6.Qd5-b5 # [/quote] 3...Bf8-d6 4.Rf1*f7 + 4...Kd7-d8 5.Qd5*d6 # [/quote] 1...Ke8-e7 2.Qf3*f7 + 2...Ke7-d8 3.Sg7-e6 # [duals 3.Qf7*d7 # and 3.Rd5*d7 #]
    1...Bf8*g7 2.Qf3*f7 + 2...Ke8-d8 3.Qf7*d7 # [dual 3.Rd5*d7 #][/quote]
  9. Joined
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    16 Apr '08 18:11
    Originally posted by SwissGambit
    Thank god I have my chess engine to spare me the hard work of actually solving this.

    1.Sf5-g7 + !
    1...Ke8-d8 2.Rd5*d7 + 2...Kd8*d7 3.Qf3-d5 + [quote] 3...Kd7-e7 4.Rf1*f7 #
    3...Kd7-c7 4.Rf1*f7 + [quote] 4...Kc7-b8 5.Qd5-b7 #
    4...Kc7-b6 5.Qd5-b5 #
    4...Bf8-e7 5.Rf7*e7 +[quote] 5...Kc7-b8 6.Qd5-b7 #
    5...Kc7-b6 6.Qd5-b5 # [/quote ...[text shortened]... f7*d7 # and 3.Rd5*d7 #]
    1...Bf8*g7 2.Qf3*f7 + 2...Ke8-d8 3.Qf7*d7 # [dual 3.Rd5*d7 #][/quote]
    Was this really necessary?
  10. Standard memberSwissGambit
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    16 Apr '08 20:19
    Originally posted by Mephisto2
    Was this really necessary?
    Permitted, yes. It has clearly been established in this thread that if we feel a problem is too hard for us to solve [or we're just too lazy to bother] we simply look it up and copy and paste the solution, or give a link [thus spoiling it for everyone else]. What I did is just as valid.
  11. Joined
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    16 Apr '08 20:42
    Originally posted by SwissGambit
    Permitted, yes. It has clearly been established in this thread that if we feel a problem is too hard for us to solve [or we're just too lazy to bother] we simply look it up and copy and paste the solution, or give a link [thus spoiling it for everyone else]. What I did is just as valid.
    Your point is taken (at least by me). However, you off all regular posters in the chess and puzzle forums should be able to understand the difference between the last two puzzles. The link you were referring to may have spoiled it for a very small number of members, but only if they decided to click on the solution link. The last puzzle, however, was within many members' reach, and the solution was posted plainly and almost impossible to ignore.
  12. Standard memberSwissGambit
    Caninus Interruptus
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    17 Apr '08 00:572 edits
    Originally posted by Mephisto2
    Your point is taken (at least by me). However, you off all regular posters in the chess and puzzle forums should be able to understand the difference between the last two puzzles. The link you were referring to may have spoiled it for a very small number of members, but only if they decided to click on the solution link. The last puzzle, however, was within many members' reach, and the solution was posted plainly and almost impossible to ignore.
    And what would have happened with the last puzzle, had I left it alone? The 'many members' would still have been beaten to the punch by the faster solvers in the crowd. The problem isn't that the solution is posted; it's that someone decides for everyone else that the problem isn't even worth solving. That's what's getting spoiled: the potential thrill of being the first to find a difficult solution to a problem that stumps everyone for awhile.
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