Originally posted by CZeke1.Bxh1 Qxh7+ 2.Kxh7 and Black's K has two light diagonals to play on. Where's the mate?
No, he's right. Say it's White's turn; he plays Bxh1. The threat of Bd5# is now unstoppable. Black can trade queens, get his queen in position to block, sac his queen for a bishop, try to escape with Kb3, whatever he likes, but mate is certain in a few moves at most. Nifty position.
Originally posted by CZekeHowever, after 1.Bxh1 Qxh7+ 2.Kxh7, Black gets his piece back by 2...Bxe3. Everything from then on out is an even trade. White can't win.
...Yeah, ignore me, I'm just making a fool of myself as I always seem to do in these puzzle topics.
I think my first move has to be correct, though. White can't prevent the exchange of queens if Black wants to make it. Since no quantity of bishops is sufficient to mate if they're all dark-squared, he's got to take the h1 bishop if he wants to win.
Originally posted by SwissGambitThe position is impossible to attain by normal play. The king is double checked by rook and bishop, but there isn't any way either of the 2 checking pieces could have been moved in a manner such that it blocked the other before the move.
[fen]8/8/2kP4/5r1b/8/6Kp/7P/2R2bBB b - - 0 1[/fen]
Is the position legal?
b) wQh1 instead of wB
Edit: Prove your answer.