12 Feb '07 02:20>
True or false:
if a, b, c and d are positive integers, and ab=cd, then a+b+c+d cannot be a prime number.
if a, b, c and d are positive integers, and ab=cd, then a+b+c+d cannot be a prime number.
Originally posted by XanthosNZif youy cant proove something, it is assumed false.
If you wish to state that it is unprovable you need to prove that this is the case.
And even if it is unprovable that doesn't mean it's false unless a counter example exists.
Originally posted by celticcountryIf you can't prove something, you assume nothing. Welcome to mathematics.
if youy cant proove something, it is assumed false.
Originally posted by ilywrinMaybe I'm being stupid, but why is this true?
Let's try this:
If ab=cd, then there exist integers x,y, z and t such that:
a=xz, b=yt, c=xt, d=yz. (one or more of these integers may be equal to 1).
Then a+b+c+d = xz+yt+xt+yz = x(z+t) + y(z+t) = (x+y)(z+t) which consists of two different integers, hence can never be a prime. Does that sound right?
Originally posted by FabianFnascelticcountry can go suck eggs. His posts in this thread earned him the title of idiot, did you read them?
And you are the only one in the whole world who is not an idiot?
How lonely you must feel...
I don't mind you calling me an idiot, I know you too good for that.
But an apology to celticcountry would be appropriate.
Originally posted by Fat LadyThat was my first thought. On second thought I think it is true, but it isn't obvious.
Maybe I'm being stupid, but why is this true?
If ab=cd, then there exist integers x,y, z and t such that:
a=xz, b=yt, c=xt, d=yz. (one or more of these integers may be equal to 1).
Originally posted by XanthosNZYes, I did, and he is cleverer than the most people of this earth.
celticcountry can go suck eggs. His posts in this thread earned him the title of idiot, did you read them?