Originally posted by DeepThought
The series 1 + 1/2 + 1/4 + ... + (1/2)^N + ... is absolutely convergent because you can write the nth partial sum as 2 - (1/2)^(N+1), so the sequence of partial sums is bounded from above by 2. This means you can reorder the sum to your hearts content and it will not change the result of the sum. It also means the sum has the property that doubling each element will increase the sum by two.
Just a few minor quibbles:
The series 1 + 1/2 + 1/4 + ... + (1/2)^N + ... is absolutely convergent because you can write the nth partial sum as 2 - (1/2)^(N+1), so the sequence of partial sums is bounded from above by 2
The first minor quibble with this is that absolute convergence is defined on the absolute values of the terms of a series.
The second minor quibble is that for a series to be convergent it isn't sufficient for it to be bounded above. The partial sums have to be increasing. Since all of the terms of this series are positive talking about the terms or its absolute values is equivalent and the partial sums are increasing.
Hence one can conclude that the series is convergent (increasing partial sums that are bounded above) and that is also is trivially absolutely convergent (the terms and their absolute values are always the same)
This means you can reorder the sum to your hearts content and it will not change the result of the sum
This is only true for absolutely convergent series. And I'm aware that you stated that the series under consideration is absolutely convergent but you didn't provide an argument for it to be so.
These quibbles of mine are only in the interest of completeness because given the content of your posts it is evident that at the very least you have an intuition about all of I just talked about,. but maybe some people that read your posts don't have it and it's nice to let things be clear as they can be.