18 Jun '12 19:09

No...wait...! (cue sound of crickets)

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converging to it18 Jun '12 21:281 editLet B be the boycott operator applied to a poster p_i, with B^2(p_i) = B(B(p_i)) denoting the boycott operator applied to the boycotter of p_i. Let n be a positive integer, and 0 be the empty boycott. Then there exists k such that for all n > k, B^n(p_i) = 0.

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2014.05.0119 Jun '12 04:57

Take it to Posers and Puzzles, Spanky.*Originally posted by Agerg***Let B be the boycott operator applied to a poster p_i, with B^2(p_i) = B(B(p_i)) denoting the boycott operator applied to the boycotter of p_i. Let n be a positive integer, and 0 be the empty boycott. Then there exists k such that for all n > k, B^n(p_i) = 0.**

Proof left as an exercise for the reader.