- 18 Jun '12 21:28 / 1 editLet B be the boycott operator applied to a poster p_i, with B^2(p_i) = B(B(p_i)) denoting the boycott operator applied to the boycotter of p_i. Let n be a positive integer, and 0 be the empty boycott. Then there exists k such that for all n > k, B^n(p_i) = 0.

Proof left as an exercise for the reader. - 19 Jun '12 04:57

Take it to Posers and Puzzles, Spanky.*Originally posted by Agerg***Let B be the boycott operator applied to a poster p_i, with B^2(p_i) = B(B(p_i)) denoting the boycott operator applied to the boycotter of p_i. Let n be a positive integer, and 0 be the empty boycott. Then there exists k such that for all n > k, B^n(p_i) = 0.**

Proof left as an exercise for the reader.