13 Jun '12 15:511 edit

dear PK, after I posted my question in a Maths forum i received this reply,

What is the chance of even a simple protein molecule forming at

random in an organic soup? Evolutionists acknowledge it to be only

one in 10 to the 113th power (1 followed by 113 zeros).

It appears that this particular claim (along with the data underlying

the beans illustration) comes from this 1980 article:

Glycolysis and Alcoholic Fermentation by Jean Sloat Morton, Ph.D.

http://www.icr.org/article/glycolysis-alcoholic-fermentation/

To illustrate, let us consider a simple protein containing only

100 aim acids. There are 20 different kinds of L-amino acids in

proteins, and each can be used repeatedly in chains of 100.

Therefore, they could be arranged in 20^100 or 10^130 different

ways. Even if a hundred million billion of these (10^17)

combinations could function for a given purpose, there is only one

chance in 10^113 of getting one of these required amino acid

sequences in a small protein consisting of 100 amino acids.

So the figure 10^113 comes from two assumptions not mentioned in the

popular version: a chain length of 100, and an arbitrary redundancy

factor of 10^17. It doesn't make use of the 100 kinds of amino acids

available, or their chirality, as illustrated by the kinds of beans

and their colors.

- Doctor Peterson, The Math Forum

<http://mathforum.org/dr.math/>

What is the chance of even a simple protein molecule forming at

random in an organic soup? Evolutionists acknowledge it to be only

one in 10 to the 113th power (1 followed by 113 zeros).

It appears that this particular claim (along with the data underlying

the beans illustration) comes from this 1980 article:

Glycolysis and Alcoholic Fermentation by Jean Sloat Morton, Ph.D.

http://www.icr.org/article/glycolysis-alcoholic-fermentation/

To illustrate, let us consider a simple protein containing only

100 aim acids. There are 20 different kinds of L-amino acids in

proteins, and each can be used repeatedly in chains of 100.

Therefore, they could be arranged in 20^100 or 10^130 different

ways. Even if a hundred million billion of these (10^17)

combinations could function for a given purpose, there is only one

chance in 10^113 of getting one of these required amino acid

sequences in a small protein consisting of 100 amino acids.

So the figure 10^113 comes from two assumptions not mentioned in the

popular version: a chain length of 100, and an arbitrary redundancy

factor of 10^17. It doesn't make use of the 100 kinds of amino acids

available, or their chirality, as illustrated by the kinds of beans

and their colors.

**As you are evidently aware, the whole argument is irrelevant for**

biological evolution, which is not a purely random process; it is only

relevant in chemical evolution, where it makes it clear that the first

protein (before there were processes available to form them) could not

have arisen randomly.biological evolution, which is not a purely random process; it is only

relevant in chemical evolution, where it makes it clear that the first

protein (before there were processes available to form them) could not

have arisen randomly.

- Doctor Peterson, The Math Forum

<http://mathforum.org/dr.math/>