First off, more duels please.
Second, what happens when an odd number of people advance in a round? Specifically, the Sprint Duel 64 IX is currently in round 2. Assuming that the players who tied both advance and that group 5 produces a clear winner there will be 19 players in the next round. How do the pairings work then?
Originally posted by GalaxyShieldnot really, in a duel if you win one game (or 50% of games) your in the next round but if theres 3 people in the group and you win 2 games (50% of games) you might not be in the next round.
Actually being in a group of 3 gives you more of a margin for error, since there are an extra 2 games to get enough points to advance.
Originally posted by Ragnorak3 players
Under what circumstances wouldn't you advance in this scenario after winning 2 games? Methinks you need to redo your maths.
D
1 vs 2 - they win one each, 3 points for both
1 vs 3 - they win one each, 3 points for both
2 vs 3 - player two wins both games and picks up 6 points
player one wins two games but is knocked out by player two who wins three.
Originally posted by trevor332v3 doesn't even need to be totally decisive if one of them gets a win and a draw they would advance and you would not. Then again, if they drew both your games, you could advance with a +2 -2 = 0 score.
3 players
1 vs 2 - they win one each, 3 points for both
1 vs 3 - they win one each, 3 points for both
2 vs 3 - player two wins both games and picks up 6 points
player one wins two games but is knocked out by player two who wins three.
Originally posted by zebanoyep thats true
2v3 doesn't even need to be totally decisive if one of them gets a win and a draw they would advance and you would not. Then again, if they drew both your games, you could advance with a +2 -2 = 0 score.
there hasn't been a duel for ages i think we need a few more