Duels

First off, more duels please.

Second, what happens when an odd number of people advance in a round? Specifically, the Sprint Duel 64 IX is currently in round 2. Assuming that the players who tied both advance and that group 5 produces a clear winner there will be 19 players in the next round. How do the pairings work then?

Eight pairs and one group of three (same for all duels).

ahhh. Thanks for the info. I hope I don't get stuck in the group of 3.

Originally posted by zebano
ahhh. Thanks for the info. I hope I don't get stuck in the group of 3.

Originally posted by GalaxyShield
Actually being in a group of 3 gives you more of a margin for error, since there are an extra 2 games to get enough points to advance.

Originally posted by trevor33
if theres 3 people in the group and you win 2 games (50% of games) you might not be in the next round.

Originally posted by Ragnorak
Under what circumstances wouldn't you advance in this scenario after winning 2 games? Methinks you need to redo your maths.

D

Originally posted by trevor33
3 players

1 vs 2 - they win one each, 3 points for both
1 vs 3 - they win one each, 3 points for both
2 vs 3 - player two wins both games and picks up 6 points

player one wins two games but is knocked out by player two who wins three.

Originally posted by zebano
2v3 doesn't even need to be totally decisive if one of them gets a win and a draw they would advance and you would not. Then again, if they drew both your games, you could advance with a +2 -2 = 0 score.