1. Joined
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    06 Oct '07 06:02
    Originally posted by smw6869
    Dear Fabian, I have never experienced the euclidial division algorithm position. How many repititions? Over and over again? For how long? Gracious sakes, i must change my diapers. Later, king of the 50's rock and roll era.

    Granny.
    You use the euclidian division algorithm whenever you divide 'by hand'. Try to divide 1/3 using pencil and paper you see that you go into a repetition quite instantly, and you realize that you can fill in the threes as long as you like.

    Those of you who don't know the euclidian division algorithm - google it.
  2. Standard memberwolfgang59
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    06 Oct '07 06:44
    Originally posted by FabianFnas
    Using the euclidian division algoritm, as you do when you divide manually without any calculator, it is easily seen that the proof is unneccesary. Prform the algoritm and you'll see by yourself.
    I should have used Fabian's argument at Uni .. life would have been so much easier!

    "... it is easily seen that the proof is unneccesary."
  3. Standard membersmw6869
    Granny
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    06 Oct '07 17:30
    Originally posted by FabianFnas
    You use the euclidian division algorithm whenever you divide 'by hand'. Try to divide 1/3 using pencil and paper you see that you go into a repetition quite instantly, and you realize that you can fill in the threes as long as you like.

    Those of you who don't know the euclidian division algorithm - google it.
    Oh Fabian darling, i shall try the algorithm "by hand", but only till i get the repetitions down correctly then i hope you will show me the more advanced form, in person maybe. Just thinking of those Rock & Roll hands of yours makes me .......oops.

    Granny.
  4. Joined
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    07 Oct '07 23:15
    Originally posted by AThousandYoung
    You snuck in an extra +1 in the fourth step without including it's partner -1. This is incorrect.
    but is it? theoretically it goes on infinitely so why can't i do that?

    If you had an infinite series you could stop after any term. so technically I haven't done anything wrong.
  5. Standard memberAThousandYoung
    or different places
    tinyurl.com/2tp8tyx8
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    07 Oct '07 23:271 edit
    Originally posted by Arachnarchist
    but is it? theoretically it goes on infinitely so why can't i do that?

    If you had an infinite series you could stop after any term. so technically I haven't done anything wrong.
    The ... implies that the pattern repeats. The pattern with more +1's than -1's is different than the pattern with equal amounts of both.

    The decimal definition of pi cannot be stopped after any term. Isn't it an infinite series?
  6. Joined
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    08 Oct '07 07:37
    Originally posted by Arachnarchist
    how about this to prove 1=0
    0= 0 + 0 + 0 + . . .
    0= (1 - 1) + (1 - 1) + (1 - 1) + . . .
    0= 1 - 1 + 1 - 1 + 1 - 1 + . . .
    0= 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + . . .
    0= 1 + 0 + 0 + 0 + . . .= 1
    This is not a proof, as we all know already.

    First - what does ... means? It means that there is a repetition of a pattern infinit number of times. It doesn't have an end.

    So when I see the expression of 1-1+1-1+... I see this as a limit with n numbers of term and n approaching infinity.

    Does this limit has a value? No, of course not. There are no last term. Using this expression as if it has a value you can easily "prove" that 1=0.
  7. Standard memberTheMaster37
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    08 Oct '07 09:58
    Originally posted by Arachnarchist
    If you had an infinite series you could stop after any term.
    No! It's an infinite series, so you HAVE to go on!
  8. not quite sure.help!
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    09 Oct '07 17:27
    Originally posted by wolfgang59
    How do you know its repeated forever?

    The whole point of mathematical proof is its VIGOUR!
    the reason that numbers and mathematical proof is vigour is because they go on infinitely. this is why we use numbers as time because they can be easily repeated and will continue on no matter what. if you can give me the highest number in the world known, ill gladly take it and add 1 to make it bigger.

    Aniways id like to move on to pi. does anybody know any puzzles that include pi? i like pie.
  9. Joined
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    09 Oct '07 17:55
    Originally posted by tournymangr
    Aniways id like to move on to pi. does anybody know any puzzles that include pi? i like pie.
    Rhubarb pie with a ball of vanilla ice with pecans and a nice hot vanilla sauce, that's what I like!
  10. not quite sure.help!
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    10 Oct '07 13:31
    Originally posted by FabianFnas
    Rhubarb pie with a ball of vanilla ice with pecans and a nice hot vanilla sauce, that's what I like!
    mmmmm....that sounds really good!! i think ill go and have some apple pie right now cuz i dont have any rhubarb 🙁
  11. Joined
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    10 Oct '07 14:08
    Originally posted by tournymangr
    mmmmm....that sounds really good!! i think ill go and have some apple pie right now cuz i dont have any rhubarb 🙁
    I like round pies, and for fun I divide its diameter with its circumference, and get another pie.😵
  12. Standard memberwolfgang59
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    11 Oct '07 17:54
    Originally posted by tournymangr
    the reason that numbers and mathematical proof is vigour is because they go on infinitely. this is why we use numbers as time because they can be easily repeated and will continue on no matter what. if you can give me the highest number in the world known, ill gladly take it and add 1 to make it bigger.

    Aniways id like to move on to pi. does anybody know any puzzles that include pi? i like pie.
    My favourite is

    http://www.redhotpawn.com/board/showthread.php?threadid=72379
  13. Standard memberAThousandYoung
    or different places
    tinyurl.com/2tp8tyx8
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    17 Oct '07 02:43
    Originally posted by FabianFnas
    This is not a proof, as we all know already.

    First - what does ... means? It means that there is a repetition of a pattern infinit number of times. It doesn't have an end.

    So when I see the expression of 1-1+1-1+... I see this as a limit with n numbers of term and n approaching infinity.

    Does this limit has a value? No, of course not. There are no last term. Using this expression as if it has a value you can easily "prove" that 1=0.
    Ah, excellent point.
  14. Joined
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    17 Oct '07 15:07
    Originally posted by tournymangr
    does anyone no the .99=1?? i do🙂
    IF you look at .99... as the Series E(sigma)9/(10^n)
    E 9/(10^n) = 9 E (1/10)^n
    It is a geomentric series so the sum of the series is a/(1-r)
    9*((1/10)/(1-1/10)= 9*(1/10)(10/9) = 9*(1/9) = 9/9 = 1
    .99... = 1
  15. Joined
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    23 Oct '07 16:47
    Originally posted by Arachnarchist
    IF you look at .99... as the Series E(sigma)9/(10^n)
    E 9/(10^n) = 9 E (1/10)^n
    It is a geomentric series so the sum of the series is a/(1-r)
    9*((1/10)/(1-1/10)= 9*(1/10)(10/9) = 9*(1/9) = 9/9 = 1
    .99... = 1
    is this your chat up line?
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