Probability question.

Probability question.

Science

Cookies help us deliver our Services. By using our Services or clicking I agree, you agree to our use of cookies. Learn More.

Cornovii

North of the Tamar

Joined
02 Feb 07
Moves
53689
13 Oct 10

It's been a long time since i did my probability module in college.

If i have two independent events occuring that both have a probability of 1/10. The probability of both of them happenning is 1/100?

Is that right?

And if i have three independent events occuring, again each event at a probability of 1/10. The probability would be 1/1000?

Have i remembered correctly?

m

Joined
07 Sep 05
Moves
35068
13 Oct 10

That's right. As long as they're independent.

P

weedhopper

Joined
25 Jul 07
Moves
8096
13 Oct 10

So, that means my chances of winning the "Pick 3"Lottery is 1 in 1000? {choose 3 numbers from 0-9 and match them all}

r
the walrus

an English garden

Joined
15 Jan 08
Moves
32836
14 Oct 10

Originally posted by PinkFloyd
So, that means my chances of winning the "Pick 3"Lottery is 1 in 1000? {choose 3 numbers from 0-9 and match them all}
Yes.

T

Joined
24 May 10
Moves
7680
14 Oct 10

Originally posted by PinkFloyd
So, that means my chances of winning the "Pick 3"Lottery is 1 in 1000? {choose 3 numbers from 0-9 and match them all}
Not sure on that one. Have you taken into account that after the first ball is picked there are less balls etc. Unless the lottery replaces the ball taken. (Haven't played this sort of lottery.) Don't ask me to calculate it though.

Already mated

Omaha, Nebraska, USA

Joined
04 Jul 06
Moves
1115383
14 Oct 10

Originally posted by mtthw
That's right. As long as they're independent.
Probably.

K

Germany

Joined
27 Oct 08
Moves
3118
14 Oct 10

Originally posted by Taoman
Not sure on that one. Have you taken into account that after the first ball is picked there are less balls etc. Unless the lottery replaces the ball taken. (Haven't played this sort of lottery.) Don't ask me to calculate it though.
If the numbers can only be picked once (though it does not appear to be the case here), it's still quite easy to calculate; the chance would be 1/(10*9*8).

Cornovii

North of the Tamar

Joined
02 Feb 07
Moves
53689
14 Oct 10

Originally posted by mtthw
That's right. As long as they're independent.
So if i have 200 independent events each with a probability of 1/100million, that would be 100million x 10`200? (that should be 10 to the power of 200)

m

Joined
07 Sep 05
Moves
35068
14 Oct 10

Originally posted by KazetNagorra
If the numbers can only be picked once (though it does not appear to be the case here), it's still quite easy to calculate; the chance would be 1/(10*9*8).
If the order mattered. If it didn't, multiply by 6 (the number of permutations of three different numbers).

m

Joined
07 Sep 05
Moves
35068
14 Oct 10
1 edit

1/(100 million)^200...or 1/10^1600

Also know as "damn near to impossible".

Cape Town

Joined
14 Apr 05
Moves
52945
14 Oct 10

Originally posted by mtthw
1/(100 million)^200...or 1/10^1600

Also know as "damn near to impossible".
Yet we shouldn't misinterpret that claim. We almost certainly do have over 200 lotery winners of loteries with worse than 1 in 100 million odds.
What is 'damn near impossible' is for the same person to win all those lotteries (and hasn't happened).

m

Joined
07 Sep 05
Moves
35068
14 Oct 10
1 edit

Originally posted by twhitehead
Yet we shouldn't misinterpret that claim. We almost certainly do have over 200 lotery winners of loteries with worse than 1 in 100 million odds.
What is 'damn near impossible' is for the same person to win all those lotteries (and hasn't happened).
Or, equivalently, to predict in advance who the 200 winners will be.

It's true, though, you've got to keep an eye on your sample space. Massively unlikely events happen all the time. As in the Richard Feynman quote in a lecture: "I was walking to class today and the funniest thing happened: I saw a car with the license plate ‘ARW 357’. Can you imagine? Of all the possible license plates, what are the chances of seeing that one?"

aw
Baby Gauss

Ceres

Joined
14 Oct 06
Moves
18375
14 Oct 10

Originally posted by mtthw
As in the Richard Feynman quote in a lecture: "I was walking to class today and the funniest thing happened: I saw a car with the license plate ‘ARW 357’. Can you imagine? Of all the possible license plates, what are the chances of seeing that one?"
The point of that quote is that it doesn't make sense to calculate the probability of an event after it already happened.
He says so himself when retelling that story.

P

weedhopper

Joined
25 Jul 07
Moves
8096
15 Oct 10

The Black Swan.

m

Joined
07 Sep 05
Moves
35068
15 Oct 10

Originally posted by adam warlock
The point of that quote is that it doesn't make sense to calculate the probability of an event after it already happened.
He says so himself when retelling that story.
I know.

The other part of the point is that you have to consider probabilities in relation to the sample space your interested in. Because if there are millions of possible things that can happen then million-to-one incidents are not unlikely.

There's a very good essay on this by Ian Stewart and Jack Cohen. Unfortunately I can't find a reference to it. But I remember one part where one of them had a bet that "a coincidence will occur" while walking through an airport in Sweden. They then bumped into someone they knew and hadn't see for ages.